A circle is centered at (7, 8) and has a radius of 11. Which of the following is the equation for this circle?

(x − 7)2 + (y − 8)2 = 121
(x − 7)2 + (y − 8)2 = 11
(x + 7)2 + (y + 8)2 = 121
(x + 7)2 + (y + 8)2 = 11

Question

A circle is centered at (7, 8) and has a radius of 11. Which of the following is the equation for this circle?

(x − 7)2 + (y − 8)2 = 121
 (x − 7)2 + (y − 8)2 = 11
 (x + 7)2 + (y + 8)2 = 121
 (x + 7)2 + (y + 8)2 = 11

AverageStudent · Answer

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what are need to solve for?
$$(a-x)^2+(b-y)^2=r^2$$

Kyky232 · Answer

~i dont know~

thats why i asked the question

AverageStudent · Answer

so, none of numbers are negative;
$$(a-7)^2+(b-8)^2=11\times11=121$$
So;
$$(a-7)^2+(b-8)^2=121$$

AverageStudent · Answer

please don't get mad, Im trying to help

Kyky232 · Answer

@averagestudent wrote:

please don't get mad, Im trying to help

im not getting mad im just confused with the question lol. Geometry really dont stick with me

AverageStudent · Answer

Oh ok. I solve it for you.

AverageStudent · Answer

up there

AverageStudent · Answer

@averagestudent wrote:

so, none of numbers are negative; $$(a-7)^2+(b-8)^2=11\times11=121$$ So; $$(a-7)^2+(b-8)^2=121$$

AverageStudent · Answer

a=x
b=y

Kyky232 · Answer

so A?

AverageStudent · Answer

Yes. Congrats!