OpenStudy (anonymous):
Lines CD and DE are tangent to circle A as shown below:
Lines CD and DE are tangent to circle A and intersect at point D. Arc CE measures 130 degrees. Point B lies on circle A.
If arc CE is 130°, what is the measure of ∠CDE?
20°
40°
42.5°
50°
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mhanifa:
You can use a simple rule:
The angle between two tangents is supplementary with minor arc.
mhanifa:
It means mCE + mCDE = 180
jhonyy9:
@extrinix
Extrinix:
@jhonyy9 wrote:
do you know this formula ?
exterior angle measure = (big arc measure - small arc measure)/2
@mhanifa wrote:
It means mCE + mCDE = 180
You guys would both be correct,
jhonyy9:
\(m\angle D = \dfrac{230^\circ -130^\circ}{2}\) simplify the top
\(m\angle D = \dfrac{100}{2}^\circ \rightarrow 50^\circ\) convert, \(m\angle D\) is \(50^\circ\)
mhanifa:
\(180^\circ = m\angle CDE + 130^\circ\) subtract 130 from both sides
\(50^\circ = m\angle CDE\) \(m\angle D\) is \(50^\circ\)