Question

help.

Answer 1

have you plugged the foromulas in yet to replace f and g?

Answer 2

Sum the expressions on the right side

Answer 3

And bring to standard form after simplification

Answer 4

its gonna be (2x^2 - 5x + 16) + (10x^2 - 7) if im remembering this stuff right

Answer 5

ah so it's c

Answer 6

thanks what about this

The amount of pop in a bottle is normally distributed with a mean of 2000 mL and a standard deviation of 62mL. If 5000 bottles of pop are filled on a production line, approximately how many bottles would contain less than 1885 mL?

Answer 7

ah, deviations and mean i don't remember very well, im guessing you know the standard deviations use, uhm lets see, 2000ml give or take 62, 2000ml time 5000 bottles uh im not sure

Answer 8

compare 1885 to 2000, it's 125, which is 2 times the standard deviation
So it's 2000mL - 2SD
If you know the SD graph thing, 68, 97, 99.7
So by 2 SD's, you only have 100-50-34-13.5 = 2.5
so it's 2.5%

So do 5000 tiems 2.5%, which is 5000 times 0.025

Answer 9

I'm not really sure how to explain it without the distribution curve lol

Answer 10

dope thanks

An apple orchard's workers pick 12,500 apples in the month of October. A sample of 300 of these apples shows that 15 of them are damaged and bruised.

What is the best estimate of the number of apples picked at the orchard in October that are bruised and damaged?

Answer 11

how do i do that

Answer 12

\[(\frac{x}{12500})12500=\frac{15}{300}(12500)\\x=\frac{15}{300} \times 12500\]

Answer 13

Convert \(\dfrac{15}{300}\) to a percent,
We can convert it to it's lowest fraction,
\(\dfrac{1}{20}\), and to find the percent just multiply it by 5 on top and bottom,
\(\dfrac{1}{20}~\dfrac{\times 5}{\times 5}\)
which equals, \(\dfrac{5}{100}\)
Then take the percent as a decimal, \(0.5\) and multiply it by \(12500\),
\(12500 \times 0.5\) which would give you: \(625\)

Answer 14

thank you all very much.

Answer 15

You're welcome.