I could REALLY use help with this!!!
@snowflake0531
@jhonyy9
So first, you want to look at your given statements, \(\color{lime}{GF = \dfrac{1}{2} GC}\) \(\color{lime}{GE = \dfrac{1}{2} GD}\) \(\color{lime}{EF = \dfrac{1}{2} DC}\) These can all be equal using transative prop. of equ., \(\color{cyan}{\dfrac{GF}{GC}=\dfrac{GE}{GD}=\dfrac{EF}{DC}}\) So, your first portion would be your given values (lime) - - - - - - 1: (lime values) | Given - - - - - - Now, the cyan values are done through the transative prop. of equ., so - - - - - - 2: (cyan values) | Transative Property of Equality - - - - - - Finally, because of the transative prop. of equ., you can assume that side-side-side is possible, so - - - - - - \(\triangle GFE\) ~ \(\triangle GCD\) | SSS
each of the values listed inside of the dashes are what youre looking for.
i dont understand
so, \(\color{lime}{GF = \dfrac{1}{2} GC}\), \(\color{lime}{GE = \dfrac{1}{2} GD}\), \(\color{lime}{EF = \dfrac{1}{2} DC}\) | Given \(\color{cyan}{\dfrac{GF}{GC}=\dfrac{GE}{GD}=\dfrac{EF}{DC}}\) | Transative prop of equ. \(\triangle GFE\) ~ \(\triangle GCD\) | SSS
Right! Okay thank you! Could I ask you for help with another one?
Sure... I'm not any good at all on it but yeah.
@extrinix there is my other question
Ok, first off you should state your given statement, \(\color{tomato}{\overline{YZ} \parallel \overline{UV}}\) [] Given Now, because they are parallel we can assume alternate interior angles to be equal, so, \(\angle YVZ\) and \(\angle UZV\) are alt int angles \(\color{yellow}{\angle YVZ = \angle UZV}\) [] If lines \(\parallel\) then alt int \(\angle\)'s \(=\) With this, we can assume, \(\color{lime}{\triangle XYZ \text{~} \triangle XUV}\) [] Def of similar polygons With ALL of this, we can identify, \(\color{cyan}{\angle YXZ = \angle VXU}\) [] Vertical \(\angle\)'s \(=\) This makes our last step easy, with the others we gave reasoning to \(AA\), so \(\color{violet}{\dfrac{XY}{XU} = \dfrac{YZ}{UV}}\) [] AA
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