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Mathematics 8 Online
JeliseWh05:

Help plsss

JeliseWh05:

Extrinix:

Remove all of the other numbers and look at \(8\) and \(4\), then you can figure it out.

Extrinix:

Similar to the example with \(Figure~6\).

JeliseWh05:

Okayy

Extrinix:

So, \(Figure~4=R_P(Figure~8)\) would be the equation.

JeliseWh05:

ok thxx

Extrinix:

Mhm, and for the describing part it's basically the same to the \(Figure~6\) one.

JeliseWh05:

Okay

Extrinix:

Also, just for a reference key, 1\(\leftrightarrow\) 2 3 \(\leftrightarrow\) 6 4 \(\leftrightarrow\) 8 5 \(\leftrightarrow\) 7

jhonyy9:

so i think 1 with 2 and 3 with 6 is correct but the next two i dont see it right

JeliseWh05:

ok thxx

Extrinix:

They are, they all are reflecting over \(\overline{n}\)

jhonyy9:

if you reflect 3 over p what result ?

jhonyy9:

1 reflect over p => ?

jhonyy9:

4 =>8 5=>7 correct over n

JeliseWh05:

I rlly struggle in math.........

Extrinix:

basically the reflection rule goes like this: \(Reflected~Figure~=~R(eflection)_\text{line of reflection}(Original~Figure)\)

Extrinix:

@extrinix wrote:
basically the reflection rule goes like this: \(Reflected~Figure~=~R(eflection)_\text{line of reflection}(Original~Figure)\)
like in the example, the original figure is \(Figure~6\) and the figure in which it crosses over the \(line~of~reflection\) to get to is your \(reflected figure\), in this case \(Figure~3\).

jhonyy9:

@extrinix wrote:
@extrinix wrote:
basically the reflection rule goes like this: \(Reflected~Figure~=~R(eflection)_\text{line of reflection}(Original~Figure)\)
like in the example, the original figure is \(Figure~6\) and the figure in which it crosses over the \(line~of~reflection\) to get to is your \(reflected figure\), in this case \(Figure~3\).
explained perfect - congrats !

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