The question is linked below. I could really use some help on this.

Question

happypotato · Answer

attachment

happypotato · Answer

@jhonyy9

Extrinix · Answer

So you need to use pythagorean theorem, $c^2=a^2+b^2$ If the legs are both 6" it should look like this, $c^2=6^2+6^2$ Now you just have to solve it,

$c^2=6^2+6^2$ $c^2=6(6)+6(6)$ $c^2=36+36$ $c^2=72$ $\sqrt{c^2}=\sqrt{72}$ $c\approx 7.5$

factor it distribute add together . square both sides to get c by itself .

So it would be approximately 7.5 inches.

happypotato · Answer

In the picture there is a two in the answer

happypotato · Answer

how am I supposed to write that?

Extrinix · Answer

It might be looking for the square root of c, which would be $\sqrt{72}$.

happypotato · Answer

are you sure?

Extrinix · Answer

That's the only answer I would be certain for, because it says to find the hypotenous, $\sqrt{72}$ is technically the hypotenous in $c^2$ form.

Extrinix · Answer

On a right triangle it's always,
$hypo^2=leg^2+leg^2$

happypotato · Answer

@extrinix wrote:

On a right triangle it's always, $hypo^2=leg^2+leg^2$

and what if it's 8" instead of 6"

Extrinix · Answer

You do the same thing and input it,
$\sqrt{c^2}=\sqrt{a^2+b^2}$

$\sqrt{c^2}=\sqrt{8^2+8^2}$
$\sqrt{c^2}=\sqrt{128}$

Extrinix · Answer

That's a quicker method I came up with, but I suggest you go the longer route.

happypotato · Answer

@extrinix wrote:

That's a quicker method I came up with, but I suggest you go the longer route.

in the question, there is no option to enter a 1 (for 128)

Extrinix · Answer

Can you send a screenshot?

happypotato · Answer

yep

happypotato · Answer

attachment

mhanifa · Answer

Your answer might be in the form of:
$$c = a \sqrt{2}$$
when a = 6, $$c = 6\sqrt{2}$$
when a = 8, $$c = 8\sqrt{2}$$

Extrinix · Answer

You'd be incorrect mhanifa, $c^2=8^2+8^2$ We need to solve this,

$c^2=8^2+8^2$ $c^2=8(8)+8(8)$ $c^2=64+64$ $c^2=128$ $\sqrt{c^2}=\sqrt{128}$

factor it out distribute add together . square both sides

So the $\sqrt{128}$ would be your answer.

Tranquility · Answer

mhanifa is not wrong.

Since it is an isosceles triangle, the hypotenuse would be $ a\sqrt{2}$
|dw:1622736263104:dw|

If you simplified your final answer, you would see this is true.

$\sqrt{128} = \sqrt{64 \times 2} = \sqrt{8^2 \times 2 } = 8\sqrt{2}$

Also, next time let's let the person asking the question get involved in the question so that they can learn (instead of doing all the work for them).

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