Question

help math below

Answer 1

@extrinix

Answer 2

Ok, so to solve this, you need to convert them into improper fractions and then find similar denominators, it would look like this:
\(5\dfrac{3}{6}\)-\(2\dfrac{1}{3}\)
Improper fractions:
\(\dfrac{5 \times 6 + 3}{6}\) - \(\dfrac{2 \times 3 + 1}{3}\)

This gets you:
\(\dfrac{33}{6}\) - \(\dfrac{7}{3}\)

Now we need to find a common denominator, so how many times can 3 go into 6? 2 times.
It would look like this:
\(\dfrac{33}{6}\) - \(\dfrac{14}{6}\)

So just solve it,
\(\dfrac{33}{6}\) - \(\dfrac{14}{6}\) = \(\dfrac{19}{6}\)

Which, when converted looks like:
\(\dfrac{19}{6}\) = \(3\dfrac{1}{6}\)

Answer 3

Oh, I see where I messed up, one moment.

Answer 4

np just look please what choice correspond to your result

Answer 5

@extrinix your result is right just look please what choice correspond with your result

Answer 6

have you get it ?

Answer 7

\[3\frac{ 3 }{ 18 } = ?\]

the last one choice

Answer 8

Ohhh okay, so basically just multiply it got it,

\(\dfrac{3}{6} \times \dfrac{1}{3}\)

Which would give you
\(\dfrac{3}{18}\)

Then separately you would do 5-2 which would give you,
\(3\dfrac{3}{18}\)

Yeah I was never taught to separate out the whole numbers, I was taught to convert it to an improper fraction...

Answer 9

Maybe it’s looking for it’s GCF?