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I could use some help with this ASAP!!!!
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@jhonyy9
@extrinix
so do you know the Pythagorean theorem ? use it to find the x value
For this we are going to use the `Pythagorean Theorem`, \(c^2=a^2+b^2\) a and b are 2 legs and c is the hypotenous, so you would get, \(c^2=8^2+10^2\) Now all we have to do is solve it,
| \(c^2=8^2+10^2\) \(c^2=64+100\) \(c^2=164\) \(\sqrt{c^2}=\sqrt{164}\) \(c\approx 13\) | simplify it add together . square both sides to get \(c\) by itself roughly 13 for x |
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ok but what about y and z values ?
It doesn't ask to find z and y values.
the missing part mean just the x value ?
i think z and y values are missing too
`Find the missing part.` \(x~=~\sqrt{. .}\)
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