Question

Find −a2 − 3b3 + c2 + 2b3 − c2 if a = 3, b = 2, and c = −3.

Answer 1

You may substitute values and solve

Answer 2

c^2 should have positive sign, but you can even cancel them before starting calculations.

Answer 3

−a2 − 3b3 + c2 + 2b3 − c2 = -a2 - b3, this is the first step
\[-3^2 - 2^3 = -9 - 8 = -17\] this is the second step

Answer 4

This is the short way, simplification first, substitution next.

Answer 5

\(−a^2 − 3b^3 + c^2 + 2b^3 − c^2\)

So you need to substitute each of the values in,
\(a=3\)
\(b=2\)
\(c=-3\)

\(-3^2-3(2)^3+-3^2+2(2)^3-(-3)^2\)

Now we can simplify it,
\(-9 -24 +16\)

So from this we can then solve it,
\(-9 -24 +16 = ?\)
\(-33 +16 = ?\)
\(-17 = ?\)

With the substitutions you end up with \(-17\).

Answer 6

like a first step add the same terms

Answer 7

+c^2 with -c^2 cancel out

Answer 8

the second and the 4th term you can adding

Answer 9

first you need simplifie thie equation and just afer that you can substitute these values