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Chemistry 17 Online
karremat:

can anyone pls help me with stoichiometry questions

KyanTheDoodle:

Oh dear, it's been a while since I've done chemistry so I don't know if I'll know the answer, but I'll give it a shot. What's the question?

karremat:

thanks

karremat:

KyanTheDoodle:

Ok so, looking at the first question: With the defeat device turned off, the car will undergo the reduction of nitrogen oxide (NO) via selective catalytic reduction by reacting NO, O2, and the urea reserve to produce nitrogen gas (N2), carbon dioxide and water vapour.

KyanTheDoodle:

The first step would be to organize every reactant and product there into an equation. Here, NO, O2 and urea (CH4N2O) are reactants, and N2, carbon dioxide (CO2), and water vapor (H2O) are the products.

KyanTheDoodle:

\[NO+O _{2}+CH _{4}N _{2}O \rightarrow N _{2}+CO _{2}+H _{2}O\]

KyanTheDoodle:

This is what it looks like right now. The next step would be to balance the equation so that the same number of each element are on both sides.

KyanTheDoodle:

There's a few problems with the equation that I just wrote out here. There's 3 nitrogen molecules on the left side and only 2 on the right. There's also 4 oxygen molecules on the left and 3 on the right. Then theres 4 hydrogen molecules on the left and 2 on the right. Carbon is fine.

KyanTheDoodle:

So you will need to multiply one side, or perhaps both, so that they end up with equal amounts of their elements.

karremat:

ok, i can do that thanks

KyanTheDoodle:

Are there any other questions on here you're confused about?

karremat:

yea

KyanTheDoodle:

Okay, which ones?

karremat:

c and e

KyanTheDoodle:

Alright. So question c builds off of the answer you got from question b. What answer did you get from question b?

karremat:

can you wait for a while sorry am still solving,

KyanTheDoodle:

Oh yeah don't worry about it, take your time.

karremat:

ok

karremat:

@kyanthedoodle wrote:
Oh yeah don't worry about it, take your time.
seriously am fed up with the work but I will try my best to do it

KyanTheDoodle:

No, I completely understand. I took AP chemistry a few years ago and it was a nightmare lol

KyanTheDoodle:

it took me a while to balance the equation myself, so I understand the frustration

karremat:

i have been trying with this equation but it cant work NO+O2+CH4N2O→N2+CO2+H2O

karremat:

unless i dont put the no 2CH4N2O + 3O2 → 2N2 + 2CO2 + 4H2O

KyanTheDoodle:

After a while this was what I got 2NO + 2O2 + 2CH4N2O → 3N2 + 2CO2 + 4H2O

KyanTheDoodle:

There isn't really the ideal way to balance equations, what I do to keep track of which ones are balanced is I'll write their symbol and a little checkmark next to them. Sometimes you have to "unbalance" an equation to balance it again, if that makes sense.

karremat:

ok will try again

karremat:

sorry for being late 2NO+O2+2CH4N2O→3N2+2CO2+4H2O

KyanTheDoodle:

That's almost right. There's 8 oxygen molecules on the right and 6 on the left.

karremat:

no it is 6 6 2 o from n 2 from o 2 from ch 4n2o

KyanTheDoodle:

On the right theres 2CO2 and 4H2O. That's four O molecules from 2CO2 and four O moluecules from 4H2O

karremat:

ok i have seen it thanks am gonna change it

karremat:

3NO+2O2+2CH4N2O→3N2+2CO2+4H2O

KyanTheDoodle:

Yep! That's right.

karremat:

sorry i fell asleep

bigblood:

is dis the question

karremat:

yes

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