can anyone pls help me with stoichiometry questions
Oh dear, it's been a while since I've done chemistry so I don't know if I'll know the answer, but I'll give it a shot. What's the question?
thanks
Ok so, looking at the first question: With the defeat device turned off, the car will undergo the reduction of nitrogen oxide (NO) via selective catalytic reduction by reacting NO, O2, and the urea reserve to produce nitrogen gas (N2), carbon dioxide and water vapour.
The first step would be to organize every reactant and product there into an equation. Here, NO, O2 and urea (CH4N2O) are reactants, and N2, carbon dioxide (CO2), and water vapor (H2O) are the products.
\[NO+O _{2}+CH _{4}N _{2}O \rightarrow N _{2}+CO _{2}+H _{2}O\]
This is what it looks like right now. The next step would be to balance the equation so that the same number of each element are on both sides.
There's a few problems with the equation that I just wrote out here. There's 3 nitrogen molecules on the left side and only 2 on the right. There's also 4 oxygen molecules on the left and 3 on the right. Then theres 4 hydrogen molecules on the left and 2 on the right. Carbon is fine.
So you will need to multiply one side, or perhaps both, so that they end up with equal amounts of their elements.
ok, i can do that thanks
Are there any other questions on here you're confused about?
yea
Okay, which ones?
c and e
Alright. So question c builds off of the answer you got from question b. What answer did you get from question b?
can you wait for a while sorry am still solving,
Oh yeah don't worry about it, take your time.
ok
No, I completely understand. I took AP chemistry a few years ago and it was a nightmare lol
it took me a while to balance the equation myself, so I understand the frustration
i have been trying with this equation but it cant work NO+O2+CH4N2O→N2+CO2+H2O
unless i dont put the no 2CH4N2O + 3O2 → 2N2 + 2CO2 + 4H2O
After a while this was what I got 2NO + 2O2 + 2CH4N2O → 3N2 + 2CO2 + 4H2O
There isn't really the ideal way to balance equations, what I do to keep track of which ones are balanced is I'll write their symbol and a little checkmark next to them. Sometimes you have to "unbalance" an equation to balance it again, if that makes sense.
ok will try again
sorry for being late 2NO+O2+2CH4N2O→3N2+2CO2+4H2O
That's almost right. There's 8 oxygen molecules on the right and 6 on the left.
no it is 6 6 2 o from n 2 from o 2 from ch 4n2o
On the right theres 2CO2 and 4H2O. That's four O molecules from 2CO2 and four O moluecules from 4H2O
ok i have seen it thanks am gonna change it
3NO+2O2+2CH4N2O→3N2+2CO2+4H2O
Yep! That's right.
sorry i fell asleep
is dis the question
yes
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