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Mathematics 7 Online
Rythmic25:

Pipe A can fill a tank in 40 minutes, while Pipe B takes 60 minutes to fill the same tank. If both pipes are used at the same time, how long will it take to fill the tank?

SmokeyBrown:

We can think of this problem in terms of the rate that each pipe fills the tank. Since Pipe A takes 40 minutes to fill the tank completely, we can say that Pipe A fills 1/40 of the tank each minute Similarly, Pipe B fills 1/60 of the tank each minute. If both Pipes are working together, how much of the tank gets filled each minute? Well, what is 1/40 + 1/60? And given that rate, how many minutes does it take for the tank to get completely filled?

Rythmic25:

It would be 80

Rythmic25:

Wouldn't you have to divide it in half or something?

SmokeyBrown:

@rythmic25 wrote:
It would be 80
So I'm not sure how you got that answer, but that can't be correct. If both Pipes are working together, they should fill the tank in less time than either pipe working alone, right? I explained one method for solving the problem, but we can try tackling it a different way if that's not making sense.

Rythmic25:

1/24?

SmokeyBrown:

Yes! Ok, that's good, both Pipes together can fill 1/24 of the tank every minute. So now, how many minutes would that take to fill the entire tank?

Rythmic25:

How would you figure out the amount of minutes it would take to fill the pipes, with the amount of information we have?

SmokeyBrown:

Sure, so we know that both pipes together fill 1/24 of the tank *every minute*; you figured that out yourself. So, if 1/24 of the tank gets filled every minute... After 1 minute, we have 1/24; after 2 minutes, we have 2/24... Eventually, the entire tank 24/24 is filled. How long does that take?

Rythmic25:

It would take 24 minutes to get it filled. Because 1/24 after 1 minute is equal to 1/24 of the pipe filled. So then I after 24 minutes it would be filled completely or, filled 24/24.

SmokeyBrown:

Yes, perfect. Good work

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