Question

Suppose you roll two number cubes and find the probability distribution for the sum of the numbers. Which two sums have the same probability distribution and would be represented with equal bars on a bar graph?
Answers
4 and 11


2 and 12


5 and 10


6 and 9

Answer 1

By any chance can I
get an explanation on it?

Answer 2

What do you think is the possible sums of two numbers? Consider numbers 1 to 6 in both cubes.

Answer 3

2 and 12?

Answer 4

By any chance, could you explain it into greater detail. I have a hard time understanding things, sorry

Answer 5

You can get sums:
2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
Now you need to determine in how many ways you get each of those sums.

Answer 6

Okay, would it be 5/10 then?

Answer 7

5

Answer 8

Can you explain how you got 5?

Answer 9

2+3 6+4 7+3 8+2, 5, 10

Answer 10

Well, you get 5 with following:
1 + 4, 2 + 3, 3 +2, 4 + 1
Total 4 ways
Now, what about 10, how many ways would it be?

Answer 11

5

Answer 12

9+1 8+2 7+3 6+4 5+5

Answer 13

No, to get 5. you need 4 ways

Answer 14

4 and 11

Answer 15

2 ways to get 4

Answer 16

and 11

Answer 17

Hello?

Answer 18

Still here.

As you were saying, to get 4, you could do 1+3, 2+2, or 3+1, for 3 possible ways.

To get 11, you can do 5+6 or 6+5, for 2 possible ways.
So, 4 and 11 would not work

Maybe we should turn our attention back to 2 and 12, as you suggested earlier?

Answer 19

to get 12 there is only one way, same thing with the 2

Answer 20

Wonderful! You're right, of course. For 2 you can only do 1+1, and for 12 you can only do 6+6.
Since there is only one way of getting 2 or 12, they would both have an equal "probability" of being rolled, which is essentially what the question was asking.
It looks like you've found your answer, then.

Answer 21

Thnk you guys for the help. Im going to post another question in a min

Answer 22

Sounds good. See you again in a bit :)

Answer 23

Thanks, @SmokeyBrown,
I was distracted, you came back to help.