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`\(a^b\)` = \(a^b\)
Use curly brackets `\( y^{12} \)` = \(y^{12}\)
Say X and Y equal 0 \( y^{12} \) / \( y^{12} \) =
Say X and Y equal zero \( 9^{15} \) x 1 / \( 9^{15} \) =
\[\frac{a^{b}}{a^{c}}=a^{b-c}\] \[\frac{y^{12}}{y^{12}}=y^{12-12}=y^0=1\]
\[9^{15} \times \frac{1}{9^{15}}=9^{15}\div 9^{-15}\] this is because \[a^{-b}=\frac{1}{a^b}\] so \[9^{15} \div 9^{-15}=9^{15-(-15)}=9^{30}\]
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Thank you so much snow! I appreciate it :)
yw~
also 0 to the power of anything is 0
@spectrum wrote:
Say X and Y equal 0 \( y^{12} \) / \( y^{12} \) =
(7(123456.789)\(^4\))\(^0\)
@spectrum wrote:
(7(123456.789)\(^4\))\(^0\)
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