Question

pre calculus help

Answer 1

@vocaloid

Answer 2

@extrinix

Answer 3

@vocaloid

Answer 4

So, the equation of a circle looks like this.
\(\color{tomato}{(x – h)^2 + (y – k)^2 = r^2}\)

So, the center point that we are given is \((-9,-2)\), which would be your \(h\) and \(k\).
\(\color{yellow}{(x + 9)^2 + (y + 2)^2 = r^2}\)

Now, the tangent to the x-axis would be where the circle comes upon the axis, so presumably that would be \((-9,0)\), which would make the radius \(2\).
\(\color{lime}{(x + 9)^2 + (y + 2)^2 = 2^2}\)

So now all you would do is solve what \(2^2\) is, which is \(4\).
\(\color{cyan}{(x + 9)^2 + (y + 2)^2 = 4}\)

Answer 5

THAT was correct thanks