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Mathematics 7 Online
Foreverangel:

Verify the identity. tanx+cotx=cscxsecx Drag an expression into each box to correctly verify the identity.

Foreverangel:

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Vocaloid:

you can re-write tan(x) as sin(x)/cos(x) you can also re-write cot(x) as cos(x)/sin(x). that gives you the sin(x)/cos(x) + cos(x)/sin(x) as the first line from there, you can make both denominators equal to cos(x)sin(x). multiply sin(x)/cos(x) by sin(x)/sin(x) and multiply cos(x)/sin(x) by cos(x)/cos(x) from there, use the identity sin^2(x) + cos^2(x) = 1 to simplify finally, use the fact that csc(x) = 1/sin(x) and sec(x) = 1/cos(x) to get your answer in terms of csc and sec can you try re-arranging the blocks now?

Foreverangel:

Im gonna be honest here I have no clue I have gone over this so many times today and havent been able to get it

Vocaloid:

I'll write out the steps in a minute ^^ I think the main two things are to remember the properties, and think about how you can use them to make both sides equal.

Foreverangel:

Alright thank you! I am gonna right this stuff down so I can have it to look at

Vocaloid:

To the right side, I also wrote the reason why the step works. Notice how the reasons are all identities or basic mathematical operations. Let me know if you have any questions about each step.

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Foreverangel:

Thank you so much! I am going to write and go over everything.

Vocaloid:

I think the hardest step to think of is the denominators step. My logic: I have two separate expressions separated by a plus sign. The final step is csc(x)sec(x). So to "combine" the fractions sin(x)/cos(x) + cos(x)/sin(x) I had to make both denominators equal to cos(x)sin(x) by multiplying by either sin(x)/sin(x) or cos(x)/cos(x) as appropriate. Because sin(x)/sin(x) and cos(x)/cos(x) are both equal to 1, I can multiply each fraction by 1 without changing the actual value of the fraction. However, changing both denominators lets us "combine" the two terms. Additionally, it also gives us cos^2(x) + sin^2(x) = 1 as the numerator, which helps us simplify the numerator. ^ that's my logic behind my steps. It's hard at first but with practice, this kind of thinking will become more natural.

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