1. What is the GCF of: 9a^4 b^4 - 27a^3b^3

2. Factor using the difference of two square methods: x^2 - 36

3. Factor the trinomial: x^2 + 7x + 10

Question

1. What is the GCF of: 9a^4 b^4 - 27a^3b^3

2. Factor using the difference of two square methods: x^2 - 36

3. Factor the trinomial: x^2 + 7x + 10

yoooweslime · Answer

@kjsaif

yoooweslime · Answer

@hhanan

yoooweslime · Answer

@0mega

yoooweslime · Answer

i really need help i have a test in an hour

hhanan · Answer

okay so for the first one you have to Find the Greatest Common Factor then Factor out the GCF then simplify it 
So you get :$$9a^3b^3(ab-3)$$

For the 2 one you have to 1 rewrite the form
$$x^2-6^2$$ then you get (x+6)(x-6)

For the 3 one the number that adds to 10 and 7 are 2 and 5 because 5+5 is 10 and 5+2 is 7
So just rewrite the expression and you get $$(x+2)(x+5)$$

I have to go so if you have any other question I might be back later

yoooweslime · Answer

@hhanan wrote:

okay so for the first one you have to Find the Greatest Common Factor then Factor out the GCF then simplify it So you get :$$9a^3b^3(ab-3)$$ For the 2 one you have to 1 rewrite the form $$x^2-6^2$$ then you get (x+6)(x-6) For the 3 one the number that adds to 10 and 7 are 2 and 5 because 5+5 is 10 and 5+2 is 7 So just rewrite the expression and you get $$(x+2)(x+5)$$ I have to go so if you have any other question I might be back later

Thank yu

surjithayer · Answer

for 3
break 7 in a+b=7
$$a \times b=10$$
7=5+2
$$5 \times 2=10$$
$$x^2+(5+2)x+10$$
$$=x^2+5x+2x+10$$
$$=x(x+5)+2(x+5)$$
$$=(x+5)(x+2)$$