Question

chemistry

Answer 1

@vocaloid

Answer 2

when you have a long hydrocarbon (compound w/ C-H only) + O2, this is a combustion reaction

so your products are CO2 and H2O

can you try balancing from there? I'll help you out if you get stuck

it might be helpful if you re-write CH2(CH2)2CH2 as C4H6 since there are 4 carbon atoms and 6 hydrogen atoms

Answer 3

how is there 4 carbon?

Answer 4

how do I balance it if theres nothing to balance from

Answer 5

like I said earlier, this is a combustion reaction, so your products are CO2 and H2O

CH2(CH)2 CH2 + O2 ---> CO2 + H2O, balance

Answer 6

i put a 3 in front of h2O

Answer 7

yes, that's a good place to start, now the hydrogen atoms are balanced - now try balancing either C or O

Answer 8

and then a 4 infront of O2 and CO2

Answer 9

I agree with putting a 4 in front of CO2, that way you balance out carbon

however, at this point notice how you have 3H2O + 4CO2 as the products. this is 11 oxygen atoms (which is an odd number, so you can't balance this with O2), so you'll need to re-balance the oxygen atoms by increasing the products.

Answer 10

hint: try doubling both H2O and CO2 to get 6H2O + 8CO2

Answer 11

how do i balance oxygen if I cnant put a 4 infront of O

Answer 12

if you double both H2O and CO2 to get 6H2O + 8CO2, you have 22 oxygen atoms (so you can now balance O2 by adding an 11 in front of O2)

all that's left now is to rebalance H and C by adding some number in front of CH2(CH2)CH2

Answer 13

so whatever number is infront of H2O multiplies all of them?

Answer 14

yup

1H2O = 2 hydrogen 1 oxygen
2H2O = 4 hydrogen 2 oxygen and so on

Answer 15

put a 2 infront of CH2?

Answer 16

yup, 2CH2(CH)2CH2 + 11O2 --> 6H2O + 8CO2 is balanced

Answer 17

theres 8 H on one side and 12 hydrogen on the other side

Answer 18

CH2(CH)2CH2 is 6 hydrogens
the first CH2 has 2
the middle (CH)2 has 2
the last CH2 has 2

then double the result to get 12

Answer 19

but why do i double the result

Answer 20

theres no paranthesis to double it

Answer 21

there's a 2 in front of it

2CH2(CH)2CH2

the 2 in front doubles every atom count

Answer 22

for combustion, H2O and CO2 are both gaseous (g)