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A quantity of steam (800 g) at 123°C is condensed, and the resulting water is frozen into ice at 0°C. How much heat was removed? last question I promise I just need help
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\(q = mc \Delta T\) m is mass which they told you is 800 grams c is the specific heat and the specific heat for water is 4.18 J/g*C \(\Delta T\) is the change in temperature and you're going from 123 degrees Celsius to 0. What is the change in temperature? q is the heat which you're solving for
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