Question

A quantity of steam (800 g) at 123°C is condensed, and the resulting water is frozen into ice at 0°C. How much heat was removed?

last question I promise I just need help

Answer 1

\(q = mc \Delta T\)

m is mass which they told you is 800 grams
c is the specific heat and the specific heat for water is 4.18 J/g*C
\(\Delta T\) is the change in temperature and you're going from 123 degrees Celsius to 0. What is the change in temperature?

q is the heat which you're solving for