Complete the equation of the line through (2,-2) and (4,1) Use exact numbers.
y = ??
solve for y
I have to get it in slope intercept form
y = mx + b
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hamidiso23:
do I stat with y2-y1
hamidiso23:
x2 - x1
hamidiso23:
start
hamidiso23:
and find the slope then put it back in the equation?
hamidiso23:
@thisgirlpretty
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ThisGirlPretty:
@umm
hamidiso23:
anyone?
ThisGirlPretty:
@dude
AN0NYM0US:
The incline catch type of the situation of a line is : y = mx + b
The incline is addressed by m and the y-catch is addressed by b.
You can utilize the directions of the two focuses to discover the incline:
m = (y 2 - y 1)(x 2 - x 1)
For this issue:
m = (4 - 2 ) = 2(1 - 2) - 1
To decide the y-block , substitute the directions of one or the other point into the slant capture condition utilizing an incline of - 2:
y = mx + by = - 2 • x + bUtilizing (1,4):4 = - 2 • 1 + b 4 = - 2 + bb = 6
The condition of the line will be : y = - 2•x + 6 The incline catch type of the situation of a line is : y = mx + b
The incline is addressed by m and the y-catch is addressed by b.
You can utilize the directions of the two focuses to discover the incline:
m = (y 2 - y 1)(x 2 - x 1)
For this issue:
m = (4 - 2 ) = 2
(1 - 2) - 1
To decide the y-block , substitute the directions of one or the other point into the slant capture condition utilizing an incline of - 2:
y = mx + b
y = - 2 • x + b
Utilizing (1,4):
4 = - 2 • 1 + b
4 = - 2 + b
b = 6
The condition of the line will be : y = - 2•x + 6
hamidiso23:
thats not the answer
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hamidiso23:
-2 times x
hamidiso23:
u sure
hamidiso23:
that was wrong
hamidiso23:
it isnt -2x +6
AN0NYM0US:
X=-y-6/2
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AN0NYM0US:
X=3 and y=6
hamidiso23:
thats wrong too
Serenity1jacksonsl:
@hamidiso23 wrote:
thats wrong too
he are she put the numbers wrong
hamidiso23:
@serenity1jacksonsl wrote:
@hamidiso23 wrote:
thats wrong too
he are she put the numbers wrong
who
AN0NYM0US:
Me
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Serenity1jacksonsl:
i was looking at the top my bad
hamidiso23:
@serenity1jacksonsl wrote:
i was looking at the top my bad
u good
KjSaif:
do you remember the rise run method I told you ?
KjSaif:
first plot the lines on a graph
hamidiso23:
down or up and over right or left
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hamidiso23:
there is no graph
KjSaif:
you can always make one
@hamidiso23 wrote:
there is no graph
you can always make one
IhelpUuHELPme:
Desmos
KjSaif:
^
hamidiso23:
ok
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hamidiso23:
its not plotting
dude:
@hamidiso23 wrote:
do I stat with y2-y1
Yes
\(m=\dfrac{y_2-y_1}{x_2-x_1}\)
(2,-2) is point 1 and (4,1) is point 2
hamidiso23:
3/2
hamidiso23:
is the slope
dude:
Yes
Now we substitute it into the general equation
y=\(\dfrac32x+b\)
From here you can choose either point 1 or 2 and substitute it in for x and y
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hamidiso23:
and 4 is the y
KjSaif:
@hamidiso23 wrote:
its not plotting
No once you plot you can start to find your answer.
You find the slope from there and then on.
dude:
If you choose point (4,1), 4 isn't the y
hamidiso23:
I choose
hamidiso23:
point 1
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hamidiso23:
-2 + 2 equals zero
hamidiso23:
2+ 2 =4
hamidiso23:
isnt it 4 for the y intercept
dude:
Not quite, you just want to substitute it in the equation we got earlier
\(y=\dfrac32x+b\)
[From point 1, (2,-2)]
2 = x
-2 = y
You'll get:
\(-2=\dfrac32\cdot2+b\)
Does that make sense?
hamidiso23:
@dude wrote:
Not quite, you just want to substitute it in the equation we got earlier
\(y=\dfrac32x+b\)
[From point 1, (2,-2)]
2 = x
-2 = y
You'll get:
\(-2=\dfrac32\cdot2+b\)
Does that make sense?
so whats the answer
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dude:
You want to isolate for b first
hamidiso23:
my brain hurts
dude:
xd
What is \(\dfrac32\cdot2\)?
hamidiso23:
3
dude:
Yes
So we have
\(-2=3+b\)
You subtract 3 from both sides
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hamidiso23:
5
hamidiso23:
-5
dude:
Right
So the equation of a line is y=mx+b
We only need m and b (which we just solved)
So we have \(y=\dfrac32x-5\)
hamidiso23:
tnx
hamidiso23:
tnx
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hamidiso23:
Complete the equation of the line through (-6,-5)( -4, -4)
Use exact numbers.
y =??
I need to answer the question in y= mx+ b format
hamidiso23:
1/2 would be slope right
dude:
Yes
dude:
Now choose one of the points and substitute it in the general equation
hamidiso23:
point 1
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hamidiso23:
(
-6, -5)
dude:
\(-5=\dfrac12\cdot-6+b\)
Do you know how to solve for b?
hamidiso23:
1/2
hamidiso23:
times -6?
dude:
Yes
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hamidiso23:
-3
dude:
\(-5=-3+b\)
Last step?
hamidiso23:
-8
dude:
Close
You would have to add 3 on both sides
hamidiso23:
8
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dude:
\(-5+3\)
hamidiso23:
-2
dude:
Righto
Putting it back into the general equation
\(y=\dfrac12x-2\)
hamidiso23:
tnx
hamidiso23:
Complete the equation of the line through (1,4) and (2,2)
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