Question

Use the fundamental theorem of algebra to determine the number of roots for 2x^+4x+7

What are the Root?

Answer 1

Roots**

Answer 2

i got 1+/- sqrt-10/2

Answer 3

I'm not sure if I can answer this or not, but can I see a screenshotof the equation 💀

Answer 4

opps i meant 2x^2+4x+7

Answer 5

\[ 1+/- \sqrt-10/2\]

Is that what you got cuz thats what it shows on my end or did you get (this is what I got)

\[x=\frac{ -2\pm i \sqrt{10}\ }{ 2 }\]

Answer 6

So that's what you got?

Answer 7

yes

Answer 8

How did you get that?

Answer 9

Well what equation do you have to use because if you know the equation that helps you a lot.

Answer 10

What do you mean?

Answer 11

I mean for example this is one I am just using as a example. Like Y=mx+b that is a equation. That is not the one you have to use but that is a equation.

Answer 12

?

Answer 13

So you know how each problem has a example equation? There is one for this one that you need to use for this. Do you know what that is?

Answer 14

The quadratic formula or completing the suqare

Answer 15

ahem

Answer 16

`Use the fundamental theorem of algebra `

Answer 17

it is of degree 2 so it has two roots by fundamental theorem of algebra.

Answer 18

you can find roots by completing squares or by using quadratic formula.

Answer 19

@surjithayer i solved by using the quadratic formula, what did I do wrong?

Answer 20

I mean to put -1 instead of 1

Answer 21

ok i redid it and got

Answer 22

\[x=\frac{ -4\pm \sqrt{4^2-4\times2\times 7} }{ 2\times2 }\]
\[x=\frac{ -4 \pm \sqrt{16-56} }{ 4 }\]
\[x=\frac{ -4\pm \sqrt{-40} }{ 4 }\]
\[x=\frac{ -4\pm 2\sqrt{-10} }{ 4 }\]
\[x=\frac{- 2\pm \sqrt{10} \iota }{ 2 }\]

Answer 23

you are correct.

Answer 24

Does it matter where i put the i

Answer 25

no

Answer 26

Thank you

Answer 27

yw

Answer 28

is it -2x^2+4x+7

Answer 29

or 2x^2+4x+7

Answer 30

Its 2x^2+4x+7

Answer 31

then you are correct.