Hey, I have a question with 2 parts that I am not sure how to do. Thank you!
Is there a screenshot of it or something?
What's the Question(s), So we can help you.
Is there a image or something you can provide?
There offline.
A 3.0 cm lighted candle is placed 20 cm from a concave spherical mirror with a radius of curvature of 30 cm. (a) Where should a screen be placed (in cm) in order to see the candle's image clearly? (Give your answer as a distance from the center of the mirror.)
sorry I had to handle something. I am back online
Ok
so what do I do for the problem
@vocaloid
A 3.0 cm lighted candle is placed 20 cm from a concave spherical mirror with a radius of curvature of 30 cm. (a) Where should a screen be placed (in cm) in order to see the candle's image clearly? (Give your answer as a distance from the centre of the mirror.) So, were given that the mirror is a concave spherical mirror, which means that the formula for it would be \( \frac{1}{F}=\frac{1}{U_{\ell}}+\frac{1}{V} \) where: \(\large\mathcal{r} _{i}\) \(= -30cm\) \( U_{\ell} =-20cm\) \( F=\frac{r_{c}}{2}=-\frac{30cm}{2}=-15cm \) plugging what we have into the formula we would get: \( - \frac{1}{15cm}=-\frac{1}{ 20cm }+\frac{1}{V} \) find the LCM: \( -\frac{1}{15cm}\times\:60v=-\frac{1}{20cm}\times\:60v+\frac{1}{v}\cdot \:60v \) \( -4v(cm)=-3v(cm)+60 \) \( -4v(cm)+3v(cm)=60 \) \( -v(cm)=60 \) \( \boxed{ v=-60(cm) }\) Looking at the answer, we can say that the screen should be settled \( 60cm \) AWAY from the centre of the candle to see a clear image of it.
thank you What is the minimum height (in cm) of the screen in order to see the candle's complete image? what about this?
minimum height (in cm) of the screen in order to see the candle's complete image basically means the magnification. the formula for that is: \( \mathrm{m_{ag}}=\frac{\mathrm{h}^{\prime}}{\mathrm{h}}=-\frac{\mathrm{v}}{\mathrm{u}} \) can you work out the answer?
so is 60 the v?
trying to figure out all of the letters lol but then it will be easy to plug in
its always NEGATIVE. so \( V=\color{red}{-}60cm \)
what is u?
like what does it represent
That's a bit rude for me to solve a problem, and the asker not to know what I even did. \(U\) is the distance ( \(\ell\) ) between the object and the mirror.
oh nevermind I see it now sorry I think I may have it
okay so it would be -60/20 correct? Isn't h'/h supposed to equal the -60/20 as well? If that's the case, I have 3 as an answer but the program says that answer is wrong
I reckon it's supposed to be negative 3cm.
I tried that as well
maybe try 2 and put the 30 in the 20s place?
It isn't 2 either
I figured it out. It's 9 because we are figuring out the screen height. Both sides must equals 3.
sweetas!
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