7y−4=−3(2−2x)

Find the equation of the line which passes through the point (−12,−9) and is parallel to the given line. Express your answer in slope-intercept form. Simplify your answer.

Question

7y−4=−3(2−2x)

Find the equation of the line which passes through the point (−12,−9) and is parallel to the given line. Express your answer in slope-intercept form. Simplify your answer.

KyledaGreat · Answer

attachment

KyledaGreat · Answer

@dukedadon

dukedadon · Answer

interesting..

CripQUEZZ · Answer

distribute first

KyledaGreat · Answer

how ?

CripQUEZZ · Answer

distribute the -3 into the parentheses

CripQUEZZ · Answer

so itll be like

-3 x 2

and

-3 x -2x

KyledaGreat · Answer

ok so like (-3 x 2) + (-3 x -2x) , correct me if i'm wrong

CripQUEZZ · Answer

yes sir

CripQUEZZ · Answer

so then ur problem will be

7y - 4 = -6 + 6x

surjithayer · Answer

$$7y-4=-3(2-2x)$$
7y-4=-6+6x
7y=6x-6+4
7y=6x-2
$$y=\frac{ 6 }{ 7 }x-\frac{ 2 }{ 7 }$$
its slope=6/7
eq. of line through (-12,-9) and slope 6/7 is
$$y-(-9)=\frac{ 6 }{ 7 }(x-(-12))$$
$$y+9=\frac{ 6 }{ 7 }(x+12)$$
or
7y+63=6x+72
7y=6x+72-63
7y=6x+9

surjithayer · Answer

or
$$y=\frac{ 6 }{ 7 }x+\frac{ 9 }{ 7 }$$

KyledaGreat · Answer

that's right the last one , thank you

KyledaGreat · Answer

@surjithayer wrote:

or $$y=\frac{ 6 }{ 7 }x+\frac{ 9 }{ 7 }$$

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