5x + 8y = 4y − 5 Find the equation of the line which passes through the point (11,12) and is perpendicular to the given line. Express your answer in slope-intercept form. Simplify your answer.
do you know what the slope intercept form is?
yes
ok so do you know how to get that equation to slope intercept form?
no
ok so u need to get the y by itself
you mean like this y =
yes
do you know how you would do that?
no indeed
ok so you do the following:\[5x-5x+8y=4y-5x-5\]\[8y-4y=4y-4y-5x-5\]\[4y=-5x-5\]
I got you to there you need to divide both sides by 4 but first do you get how i got 4y=-5x-5?
not exactly per se
and how do i divide both sides by 4, i'm sorry i wasn't all that good with math
its ok. the first thing i did was subtract 5x from both sides. Then i subtracted 4y from both sides.
do you get that?
yes sort of , i'm just trying to figure out how to divide from both sides in simpler times for me to get it
yes sort of , i'm just trying to figure out how to divide from both sides in simpler times for me to get it
terms i meant
so one side has 4y and we need to get the y by itself right?
yes
ok so you divide 4y by 4 to get y all by itself
but what you do to one side of the equal sign you have to do to the other side
so you take -5x-5 and divide it by 4
okay , is it -5x - 5/4 ?
so the equation now would be y=-1.75x-1.75
-1.75
ok but it wants the perpendicular equation that lines up with (11,12)
i see , how could i get it up to there ?
i think i might be right or wrong , is it y = 4/5x + 16/5 ?
i am trying to figure that out rn. its been a while since i have done these things
i understand , i've been out of school since may as i graduated and all this bring me back so i get what you mean lol
I am a super senior in high school
how did you get that equation?
basically, i looked back and i know that it would have to be y - y1 = m(x - x1) to find the line perpendicular
that is the correct answer but I have no clue how you got it.
thank you , i seen from an example . i'll show you
ok
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