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chemistry help please
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@vocaloid
for I: look up Iodine's atomic number. that's how many protons iodine will have. because it's I- (negative 1 charge), number of electrons is 1 more than the # of protons because it has a negative charge, it's an anion second row: look up which atom has atomic # 12. it has fewer electrons than protons so it must be a positive ion (cation). the charge becomes (# of protons - # of electrons). no idea how you're supposed to solve row 3 as there is not enough information
is there really not enough information isn't there any sort of way?
@darkknight
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i figured it out its Ge
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