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Chemistry 23 Online
Mathplayer223:

chemistry help please

Mathplayer223:

1 attachment
Mathplayer223:

@vocaloid

Vocaloid:

for I: look up Iodine's atomic number. that's how many protons iodine will have. because it's I- (negative 1 charge), number of electrons is 1 more than the # of protons because it has a negative charge, it's an anion second row: look up which atom has atomic # 12. it has fewer electrons than protons so it must be a positive ion (cation). the charge becomes (# of protons - # of electrons). no idea how you're supposed to solve row 3 as there is not enough information

Mathplayer223:

is there really not enough information isn't there any sort of way?

Mathplayer223:

@darkknight

Mathplayer223:

i figured it out its Ge

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