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Solve the linear equation `2(3x+2)=2x-1+x`. State the property that justifies your first step and why you chose it.
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So to start off, let's use the `distributive property` and simplify the equation \(2(3x+2)=2x-1+x\) \(6x+4=2x-1+x\) Now we can solve for \(x\) \(6x+4=2x-1+x\) Combine like terms \(6x+4=3x-1\) Subtract 3x from both sides \(3x+4=-1\) Subtract 4 from both sides \(3x=-5\) Divide by 3 on both sides, and you have \(x\) \(x=-\dfrac{5}{3}\)
@extrinix wrote:
So to start off, let's use the `distributive property` and simplify the equation
\(2(3x+2)=2x-1+x\)
\(6x+4=2x-1+x\)
Now we can solve for \(x\)
\(6x+4=2x-1+x\)
Combine like terms
\(6x+4=3x-1\)
Subtract 3x from both sides
\(3x+4=-1\)
Subtract 4 from both sides
\(3x=-5\)
Divide by 3 on both sides, and you have \(x\)
\(x=-\dfrac{5}{3}\)
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