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Mathematics 16 Online
sxdsouls:

maf help plssssssssssssssssssssssssss

sxdsouls:

System of Equations by Elimination

sxdsouls:

16x-4y=28 -8x+3y=-5

dude:

You want both numbers to cancel each other out You can choose to remove either variable, which one do you want to remove? x or y?

sxdsouls:

y

sxdsouls:

brb rq

XioGonz:

You have to add the equations in order to solve for the first variable

XioGonz:

After that you'll get your value. You have to plug that value into the other equations in order to solve for the remaining variables

sxdsouls:

"plug" ?

dude:

kk You want to find the lowest common factor between 4 and 3 Should be pretty straight forward 3: 3,6,9,[12],15,18,21 4: 4,8,[12],16,20 Lowest common factor is 12 Multiply each equation by its respective factor to get 12y \(3\times(16x-4y=28)\)= \(48x-12y=84\) \(4\times(-8x+3y=-5)\)= \(-32x+12y=-20\) We have: \(48x-12y=84\) \(-32x+12y=-20\) Now you can add them up Does this make sense?

sxdsouls:

Ok makes tiny bit sense

dude:

mm what confuses you?

sxdsouls:

e v e r y t h i n g

sxdsouls:

1 attachment
sxdsouls:

this part

sxdsouls:

add ?

dude:

Yes add them up \[~~~~~~~48x−12y=84 \\+−32x+12y=−20\\ \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\]

dukedadon:

look at dude man, so inspirational.

sxdsouls:

"different signs you subtract and take the sign of the bigger number" right ?

dude:

sxdsouls wrote:
e v e r y t h i n g
The main point here is to get rid of a variable when you add both equations If you want a variable to cancel itself you want the equation to have a positive and equal negative value What I did first was to find a value that both 4 and 3 shared (which was 12) Once I found the shared value I multiplied the equation so that they both had 12y or -12y Does this make more sense?

dude:

sxdsouls wrote:
"different signs you subtract and take the sign of the bigger number" right ?
Yes

sxdsouls:

(4,3) is the answer I assume now

dude:

Close y isn't 3 Once you have x, you can just substitute it into either equation Easiest would be to substitute into the second equation (You can do it with the first too) \(-8x+3y=-5\) \(-8\cdot4+3y=-5\) \(-32+3y=-5\) \(3y=27\) \(y=9\)

sxdsouls:

Jesus,

sxdsouls:

Hey I tried tho

sxdsouls:

Thank you, Appreciate your time <3

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