Find a formula for the quadratic function depicted in the following graph.
@vocaloid
The vertex form of a quadratic equation is y = a(x - h)^2 + k where (h, k) is the vertex and a is a constant what is the vertex in your graph?
i can't say
How about now? Can you figure out what the vertex is
(-4, -4) if i'm not mistaken
uhh what is this point?
-1
am i right
that's not the x-coordinate nor is it the y-coordinate
(1, -4)
There you go, now replace it in the vertex form I shared above and you'll get y = a(x-1)^2 - 4 and now to find out the value of a, just plug in a point from the graph and solve for a For example, the point (0, -4)
My bad, the point on the graph is (0, -3) y = a(x-1)^2 - 4 so if you plug in the point (0, -3) x = 0 and y = -3 What does a = ?
-3 = a(0-1)^2 - 4 a = 1
?
Exactly so now that you know a = 1 and that the vertex is (1, -4) so h = 1 and k = -4 What is the formula for the quadratic function?
y = a(x - h)^2 + k f(x) = (1x2)^2 + 1 + -4
is this right ?
You have to keep the numbers together f(x) = 1(x+1)^2 -4 and 1 outside of the parenthesis multiplied by that changes nothing so it's simply f(x) = (x-1)^2 - 4 If you want, you can simplify it by expanding (x-1)^2 and adding/subtracting any like terms. That's probably the answer they'd want you to submit
f(x) = (x-1)^2 - 4 is right , thank you
No problem!
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