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Mathematics 19 Online
KyledaGreat:

Find a formula for the quadratic function depicted in the following graph.

KyledaGreat:

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KyledaGreat:

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KyledaGreat:

@vocaloid

Tranquility:

The vertex form of a quadratic equation is y = a(x - h)^2 + k where (h, k) is the vertex and a is a constant what is the vertex in your graph?

KyledaGreat:

i can't say

Tranquility:

How about now? Can you figure out what the vertex is

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KyledaGreat:

(-4, -4) if i'm not mistaken

Tranquility:

uhh what is this point?

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KyledaGreat:

-1

KyledaGreat:

am i right

Tranquility:

that's not the x-coordinate nor is it the y-coordinate

KyledaGreat:

(1, -4)

Tranquility:

There you go, now replace it in the vertex form I shared above and you'll get y = a(x-1)^2 - 4 and now to find out the value of a, just plug in a point from the graph and solve for a For example, the point (0, -4)

Tranquility:

My bad, the point on the graph is (0, -3) y = a(x-1)^2 - 4 so if you plug in the point (0, -3) x = 0 and y = -3 What does a = ?

KyledaGreat:

-3 = a(0-1)^2 - 4 a = 1

KyledaGreat:

?

Tranquility:

Exactly so now that you know a = 1 and that the vertex is (1, -4) so h = 1 and k = -4 What is the formula for the quadratic function?

KyledaGreat:

y = a(x - h)^2 + k f(x) = (1x2)^2 + 1 + -4

KyledaGreat:

is this right ?

Tranquility:

You have to keep the numbers together f(x) = 1(x+1)^2 -4 and 1 outside of the parenthesis multiplied by that changes nothing so it's simply f(x) = (x-1)^2 - 4 If you want, you can simplify it by expanding (x-1)^2 and adding/subtracting any like terms. That's probably the answer they'd want you to submit

KyledaGreat:

f(x) = (x-1)^2 - 4 is right , thank you

Tranquility:

No problem!

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