Question

In his fish pond, Graham has goldfish and clownfish in the ratio 4:7. If he adds 6 more
goldfish, he has the same number of each type of fish. How many fish did he have in the
first place?

Answer 1

So let's start off by finding the total amounts of each fish type

We are giving 4:7 goldfish to clownfish, and if you add 6 goldfish, it equals the amount of clownfish, as stated, so we need to figure out what times what gives you an answer on both sides that equals the other

\(7\times ? = 4\times ?+6\)

This would lead you to \(2\), given that both equal to \(14\)

\(7\times 2 = 4\times2+6\)
Both equal \(14\)

So, given that 6 fish were added to the goldfish to equal the clownfish, you subtract \(6\) from the \(14\) to get the amount of goldfish

\(14-6=Goldfish\)
\(8=Goldfish\)

So that leaves you with
\(14=Clownfish\)
\(8=Goldfish\)

Answer 2

thanks for your swift reply

Answer 3

No problem ^^