Consider the following function.
Is there more to the question?
yes
alright so whats the parent function
(X + 5)^3
basic function is \[f(x)=\frac{1}{x^2}\]
ok , which ones are right ?
@snowflake0531
@tranquility
@vocaloid
@snowflake
Parent function is y=1/x^2. To look at whether they shifted up or down (vertically) or across (horizontally) it is important to know how this graph works. When a graph has any number outside of the actual variable such as the 2 in 6x-2, or the 5 in x^2+5, it means that it is performing a vertical shift. All it simply is doing is, it is shifting up and down. if negative, it shifts down vertically, and positive will shift up vertically. When a number such as (x-2)^2, the 2 WITH the x variable that is being added or subtracted is the horizontal stretch. let's consider an equation: \[1/(x+5)^2\] This is a horizontal stretch. However, it says (x+5), so you would move left 5 times. if it had said (x-5) it would move right 5 times. Lastly, if there is a negative or positive sign behind the whole equation, it is a reflectional change. Negative will flip the whole equation beside the x axis, and you would keep it standard if positive.
really
Huh?
for what you said
yes. lol.
ok can you check if my answers right
Yep
Horizontal Shift Left and 5 units correct ?
Yes
Vertical Stretch/Compress Stretch 4 units
is that correct
Where did you get four from
in the graph , i saw the wrong place
i think
it was a compress i believe
There is no four in this post you posted a pic of.
oh i'm sorry , i had the answer wrong on there ... could you point it out to me to know what it is
What number is in that equation other than the 5
3
What is done to that 3?
-
subtracted
So what would that mean
it's -3
yes, so what does that do to the graph?
ummm
It would shift the graph vertically down by 3
okay , i got that x axis is no y axis is yes correct ?
No, the negative out front is a reflection on the x axis
oh my mistake
is it right
Yes
ok i need help on something else
I'm doing homework atm. But feel free to make a new post.
okay i understand
Join our real-time social learning platform and learn together with your friends!