Find the factors for....X^3-2x^2-2x+2=0
separate into two groups (x^3-2x^2) - (2x-2) (the sign changes in the second parentheses since we essentially factored out -1 factor both sets of parentheses. starting with the first set: (x^3-2x^2) ---> GCF is x^2, giving us x^2 * (x-2) repeat this process with the second set of parentheses you'll have something in the form A(B) - C(B) in which case you'll apply the opposite of the distributive property to get the expression in the form (A-C)(B) where (A-C) and (B) are the factors. apply this logic to your problem to get the two factors.
could you show me the full working please...???
can you try factoring out the GCF from (2x-2)?
2(x-1)
then what.?
oh hm, I just realized this doesn't have integer factors. let me think for a bit.
Yeah mhmm Can you make sure you copied your question correctly? If it's 2x^3 instead of x^3 then it's factorable
The equations is correct. This is the reason I put this equation up if someone oit there has the knowledge to solving this.
correction....out there....
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