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Mathematics 11 Online
votecity20:

Find the factors for....X^3-2x^2-2x+2=0

Vocaloid:

separate into two groups (x^3-2x^2) - (2x-2) (the sign changes in the second parentheses since we essentially factored out -1 factor both sets of parentheses. starting with the first set: (x^3-2x^2) ---> GCF is x^2, giving us x^2 * (x-2) repeat this process with the second set of parentheses you'll have something in the form A(B) - C(B) in which case you'll apply the opposite of the distributive property to get the expression in the form (A-C)(B) where (A-C) and (B) are the factors. apply this logic to your problem to get the two factors.

votecity20:

could you show me the full working please...???

Vocaloid:

can you try factoring out the GCF from (2x-2)?

votecity20:

2(x-1)

votecity20:

then what.?

Vocaloid:

oh hm, I just realized this doesn't have integer factors. let me think for a bit.

Tranquility:

Yeah mhmm Can you make sure you copied your question correctly? If it's 2x^3 instead of x^3 then it's factorable

votecity20:

The equations is correct. This is the reason I put this equation up if someone oit there has the knowledge to solving this.

votecity20:

correction....out there....

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