Consider the following relation. x=−4|y|+3 Find four points contained in the inverse. Express your values as an integer or simplified fraction.
@tranquility
This question looks familiar. What is the inverse?
-4x + 3
Don't forget to keep the y = Also there should be absolute values around the x y = -4|x| + 3
x values: -2, -1, 0, 1, 2
Do you know how absolute value works? When you're plugging in those numbers to find the corresponding y-values: y = -4 |x| + 3 When x is -2 y = -4 |(-2)| + 3 The absolute value of -2 is going to be 2. Any negative number becomes positive Positive numbers stay the same y = -4*2 + 3 y = -8 + 3 y = -5 The point is (-2, -5)
Repeat this for x = -1, 0, and 1
When x is -1 y = -4*1 + 3 y = 7 + 3 y = 10 (-1, 10)
Check your work again -4* 1 is -4 What is -4 + 3
-1
So your point is going to be (-1, -1) You can also check the graph: https://www.desmos.com/calculator/uvmvin3tiy
When x is 0 y = -4*0+ 3 y = 3 + 3 y = 6 (0, 6)
Where did you get 3 + 3 from?
y = (-4*0)+ 3 Simplify it again
3
Now you got it. What's the point if y is 3 when x is 0
i'm not sure to be honest
3 + 0
is this right
(x, y) When x is 0, y is 3 (0, 3)
1 When x is 1 y = -4*1+ 3 y = 1 + 3 y = 4
Once again, I'm not sure why you've been making the same mistake again and again
y = -4|x| + 3 when x = 1 y = -4|1| + 3 |1| is equal to 1 so y = (-4*1) + 3 what is y equal to?
-1
That is correct
Just think of the | | as some sort of special parenthesis which just turns the number inside to become positive
oh okay
(1,-1)
Yes
Consider the following relation. x=−4|y|+3 Find the domain and range of the inverse. Express your answer in interval notation.
Domain : \[(-\infty,\infty)\]
i don't think so if the range is right \[(-\infty, 3]\]
is that right
@tranquility
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