Find a formula for the inverse of the following function, if possible. or does not have an inverse function
\[h(x) = \sqrt[3]{x^3+ 3} + 3\] \[h^{-1}(x) =\]
@Tranquility
(x^3/3)
@tranquility
All you need to do is solve for y now What do you get when you take the 3 to the other side?
d\[y = \sqrt[3]{x^3 - 9x^2 + 27x - 30}\]
No
I'm not sure how you got that inside the cube root
Oh wait, you're saying that as your final answer mhmm Let me check, I haven't even gotten that far yet
\(x = \sqrt[3]{y^3+ 3} + 3\) (x - 3)^3 - 3 = y^3 y = cube root of all that so it looks correct
Yeah that's correct for the inverse
alright , which one should i enter to be correct ?
I would think that the program should accept both answers
no it didn't , i have to try another one . Could you check and see the other one
cube root of (x - 3)^3 - 3
oh ok , i posted a new one
sure
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