Question

When potassium metal is placed in water, a large amount of energy is released as potassium hydroxide and hydrogen gas are produced in the reaction 2K(s) + 2H2O(l) → 2KOH(aq) + H2(g). Your lab partner says this is a redox reaction and a combustion reaction. Do you agree? Defend your answer by explaining whether or not it meets the requirements of each type of reaction.

Answer 1

Two parts to this question:

1. Is it a combustion reaction?
Combustion reactions must have heat energy as well as oxygen as a reactant. Think about whether this applies to the reaction or not.

2. Is it a redox reaction?
For a redox reaction, one of the reactants must lose electron(s) and the other must gain them. Calculate the oxidation states for all elements in the reactants vs products. If it’s a redox reaction you should see one element decreases the oxidation state between the reactant and the product, and another element should increase its oxidation state.

Answer 2

Hmmm idk this kinda confusing

Answer 3

start one step at a time:

1. is it a combustion reaction? did they add oxygen and heat to the reaction? re-read the problem.

Answer 4

Yes i am pretty sure they added oxygen and heat to the reaction

Answer 5

Look at the equation:

2K(s) + 2H2O(l) → 2KOH(aq) + H2(g).

there is no oxygen, and there the problem never said they added heat.

therefore, this is not a combustion reaction.

now, for the second part of the question, like I mentioned, calculate the oxidation states for all the elements in each compound.

Answer 6

for combustion the compound needs to react with elemental oxygen, O2

Answer 7

please review oxidation rules: https://www.thoughtco.com/rules-for-assigning-oxidation-numbers-607567

Answer 8

It is a redox reaction

Answer 9

good, just make sure to show your work in your answer

Answer 10

Ok so 2 K + 2 H2O → 2 KOH + H2

2 HI + 2 e- → 2 H0 (reduction)

2 K0 - 2 e- → 2 KI (oxidation)

Is this correct?

Answer 11

Did you copy-paste this from somewhere? the formatting doesn't make sense.

Answer 12

https://snipboard.io/HtTlU5.jpg

Answer 13

Yeah please don't submit copy-pasted work, that's not ok.

Anyway, you need to show how you assigned oxidation numbers. Notice how they gave solid potassium an oxidation state of 0, since all pure elements get 0. In KOH, K gets an oxidation state of 1. That's because the ion OH has a charge of -1 and since KOH is neutral, K needs to be +1 to balance it out.

So, since K went from 0 to 1, that means K lost an electron, and thus K got oxidized.

Repeat this logic for the reduction step.

Answer 14

https://brainly.com/question/25458014?referrer=searchResults

Answer 15

just go on this link I sent you and I think you will be pleased with the answers you get

Answer 16

Wow u so funny brooo no type of help