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Mathematics 14 Online
kingksavge:

Seth is using the figure shown below to prove the Pythagorean Theorem using triangle similarity: In the given triangle DEF, angle D is 90° and segment DG is perpendicular to segment EF. The figure shows triangle DEF with right angle at D and segment DG. Point G is on side EF. Part A: Identify a pair of similar triangles. Part B: Explain how you know the triangles from Part A are similar. Part C: If EG = 2 and EF = 8, find the length of segment ED. Show your work.

kingksavge:

alexis1800xp:

do you have your 2 triangles?

kingksavge:

Yeah EGD and FGD

alexis1800xp:

ok good

kingksavge:

I really just need Part C

alexis1800xp:

you know the pythagoreon theorum right?

kingksavge:

yeah a squared plus b squared equals c squared

alexis1800xp:

ok so EG= 2 so that a squared

kingksavge:

So is EF=8 b squared

alexis1800xp:

do you know what perpendicular means?

kingksavge:

Yes

alexis1800xp:

ok give me one sec

alexis1800xp:

do you know what DG is?

kingksavge:

Isnt it 2?

kingksavge:

So 2 squared plus 2 squared is 2.8 so is it 2.8

alexis1800xp:

mm i dont believe so let me check.

alexis1800xp:

i want to say GD is =GF

kingksavge:

I think it is

alexis1800xp:

so 2 squared + 8 squared = c squared

kingksavge:

that would be 8.25 it cant be that because that would mean ed is longer than ef

alexis1800xp:

oh sorry i meant 2 squared + 6 squared = c squared

kingksavge:

how did you get the 6 squared

alexis1800xp:

GF= 6

alexis1800xp:

If EG=2 and EF=8 then EF-EG=GF so 8-2=6

kingksavge:

ok

kingksavge:

thanks

alexis1800xp:

sorry it took so long its been a couple years since ive done geometry

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