Seth is using the figure shown below to prove the Pythagorean Theorem using triangle similarity: In the given triangle DEF, angle D is 90° and segment DG is perpendicular to segment EF. The figure shows triangle DEF with right angle at D and segment DG. Point G is on side EF. Part A: Identify a pair of similar triangles. Part B: Explain how you know the triangles from Part A are similar. Part C: If EG = 2 and EF = 8, find the length of segment ED. Show your work.
do you have your 2 triangles?
Yeah EGD and FGD
ok good
I really just need Part C
you know the pythagoreon theorum right?
yeah a squared plus b squared equals c squared
ok so EG= 2 so that a squared
So is EF=8 b squared
do you know what perpendicular means?
Yes
ok give me one sec
do you know what DG is?
Isnt it 2?
So 2 squared plus 2 squared is 2.8 so is it 2.8
mm i dont believe so let me check.
i want to say GD is =GF
I think it is
so 2 squared + 8 squared = c squared
that would be 8.25 it cant be that because that would mean ed is longer than ef
oh sorry i meant 2 squared + 6 squared = c squared
how did you get the 6 squared
GF= 6
If EG=2 and EF=8 then EF-EG=GF so 8-2=6
ok
thanks
sorry it took so long its been a couple years since ive done geometry
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