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Mathematics 17 Online
Vocaloid:

Seth is using the figure shown below to prove the Pythagorean Theorem using triangle similarity: In the given triangle PQR, angle P is 90° and segment PS is perpendicular to segment QR. The figure shows triangle PQR with right angle at P and segment PS. Point S is on side QR. Part A: Identify a pair of similar triangles. (2 points) Part B: Explain how you know the triangles from Part A are similar. (4 points) Part C: If RS = 4 and RQ = 16, find the length of segment RP. Show your work. (4 points)

Vocaloid:

posting on behalf of @iSuckAtMath101

iSuckAtMath101:

carmelle:

Alright, so we know triangle QPR is a right triangle. can you find another similar triangle which is a right triangle?

iSuckAtMath101:

psq?

iSuckAtMath101:

wait no

iSuckAtMath101:

QPR?

carmelle:

correct, it would be QSP So you already have the answer to part A. △QPR ~ △QSP

carmelle:

understood?

iSuckAtMath101:

yes

carmelle:

ok, so now lets prove how these two triangles are similar. are you familar with the AA similarity theorem?

iSuckAtMath101:

angle angle?

carmelle:

yes, can you define it?

iSuckAtMath101:

when two angles are congruent it means that the triangles are similar?

carmelle:

correct, The formal definition is: `In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar.` So now, what two angles in these two triangles are similar? I suggest you to draw it out so you can have a visual of how the triangles look like.

iSuckAtMath101:

q and r?

carmelle:

Are you sure...? look at this drawing, which angles are similar? |dw:1639519999401:dw|

iSuckAtMath101:

p and s?

carmelle:

thats right, can you find another pair?

iSuckAtMath101:

r and p

iSuckAtMath101:

or q and q

carmelle:

yep, those can work, so for part B, just state 2 pairs of angles that are similar and your reasoning will be based off of the AA similarity theorem

iSuckAtMath101:

alright

iSuckAtMath101:

Part B: angles P and S, and R and P are congruent because of the AA similarity theorem

carmelle:

Now for part C, we will have to set up a proportion with the side lengths that are given... do you have an idea of what the proportion will be/look like, or do you want me to walk you through it?

carmelle:

@isuckatmath101 wrote:
Part B: angles P and S, and R and P are congruent because of the AA similarity theorem
correct :)

iSuckAtMath101:

you can walk me through it please

carmelle:

alright, so we are given RS (which is 4) and RQ (which is 16) and we need to find RP Our proportion will look like: \[\frac{ RQ }{ RP } = \frac{ RP }{ RS }\] it might seem hard but just trust me here... just substitute the variables that are given and solve... \[\frac{ 16 }{ RP } = \frac{ RP }{ 4 }\] its easier to look at it like this \[\frac{ 16 }{ x } = \frac{ x }{ 4 }\] Now we just solve for x, can you do that? `(if you are having difficulty, just remember to cross multiply)`

iSuckAtMath101:

64 = x(squared)? then square root of 64 = 8?

carmelle:

yep, you got it, great job :D `x = 8 which means RP = 8` just remember to show your work and you'll be done :)

iSuckAtMath101:

ty so much, and ty for not giving me the answer and making me work for it lol. It helped me and now I know how to do it!!

carmelle:

@isuckatmath101 wrote:
64 = x(squared)? then square root of 64 = 8?
oh and i just wanna add, when you solve, you have to solve for x^2 as well

carmelle:

@isuckatmath101 wrote:
ty so much, and ty for not giving me the answer and making me work for it lol. It helped me and now I know how to do it!!
you're welcome!!

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