Question

help

Answer 1

I got you tet B)

Answer 2

\[2x^2-4x^2+4x+2x+3+3\]

Answer 3

\[2x^2-4x^2+4x+2x+6\]

Answer 4

\[-2x^2+4x+2x+6\]

Answer 5

final answer: \[-2x^2+6x+6\]

Answer 6

So C

Answer 7

\[(2x^2+4x+3)-(4x^2-2x-3)=\]
First, we want to distribute the Negative to the right side.
\[(2x^2+4x+3)+−1(4x^2−2x−3)=\]
\[(2x^2+4x+3)+−1(4x^2)-1(−2x)-1(−3)=\]
\[=2x^2+4x+3−4x^2+2x+3\]
Now we want to combine like terms:
\[2x^2+4x+3-4x^2+3+2x+3\]
\[(2x^2-4x^2)+(4x+2x)+(3+3)=\]
\[-2x^2+6x+6\]
Final Answer:
\[-2x^2+6x+6\]
Which is answer C.) !!

Answer 8

Thanks joe