Question

did i get this right

Answer 1

get what right theres nothing :P

Answer 2

they didnt show a triangle

Answer 3

ok so how do we do that

Answer 4

so is this the equation i have so far: 4^2+b^2=5^2

Answer 5

so i got 16+b^2=25

Answer 6

b^2=9

Answer 7

3

Answer 8

so the answer is 3

Answer 9

the answer isnt 3

Answer 10

i put 90 before and i got that wrong

Answer 11

mmh

Answer 12

\[\sin Q=\frac{ 4 }{ 5},\]\[\cos Q=\sqrt{1-\sin ^2Q}\]\[=\sqrt{1-(\frac{ 4 }{ 5 })^2}\]\[=\sqrt{1-\frac{ 16 }{ 25 }}\]
\[=\sqrt{\frac{ 25-16 }{ 25 }}\]\[=\sqrt{\frac{ 9 }{ 25}}\]\[=\frac{ 3 }{ 5 }\]
\[Q \le 90,\cos Q \ge 0\]
as P+Q=90
P=90-Q
\[\cos P=\cos (90-Q)\]\[=\sin Q=\frac{ 4 }{ 5}\]
\[\cos P+\cos Q=\frac{ 4}{ 5 }+\frac{ 3}{ 5}=\frac{ 4+3 }{ 5 }=?\]