Question

help

Answer 1

rule for dividing with negative exponents
\[x^{-a}=\frac{ 1 }{ x^a }\]
so \[7^{-2}=\frac{ 1 }{ 7^{2}}\]

Answer 2

tet

Answer 3

do u not have mathway or sum?

Answer 4

photomath?

Answer 5

note that the final outcome can never be negative when dealing with exponents

Answer 6

they literally explain stuff to u

Answer 7

It gives them the answer, it also defeats the purpose of the user learning from others on this site ~

Answer 8

not photmath

Answer 9

they explain

Answer 10

okay yall dont argue just help if you are going to help and if you arent then stop typin

Answer 11

jeez u can't have opinions here

Answer 12

i dont know how to simplify exponents

Answer 13

so x^2 is simply x multiplied by itself

Answer 14

and combine like terms tet

Answer 15

Do you even know what 1^2 is tet ;-;

Answer 16

yea it would basically be 1x1

Answer 17

or atleast i think

Answer 18

yeah exactly so 7^2 is the same as 7 x 7

Answer 19

49?

Answer 20

correct

Answer 21

i prefer english i do not like math

Answer 22

whats the minus sign for tho?

Answer 23

the minus sign tells us that the outcome of 7^2 will be a denominator.

so instead of 49 or 49/1 the answer would be 1/49

7^2 = 49
7^-2=1/49

Answer 24

\(7^{-2}\)

To figure this out, you need to create the inverse of the equation, making the exponent positive
\(7^{-2}\) using the rule:

\(a^{-b} = \dfrac{1}{a^{b}}\)

When converted you would get:
\(7^{-2} = \dfrac{1}{7^{2}}\)

Now you can simplify it:
\(7^{-2} = \dfrac{1}{7 \times 7}\)

So, what would you get from this?
\(7^{-2} = \dfrac{1}{7 \times 7}\)

Answer 25

so if there is a - sign then that means it will be a denominator 100%?

Answer 26

yes but for the exponent and not the base

Answer 27

If it’s a negative exponent, you flip the numerator and denominator and make the exponent positive

Answer 28

okay i think i get it now, i was just a little confused about the minus sign

Answer 29

@winsthumb