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\[\frac{(3s^{-3})^5}{3s^{-2}} \]
The exponent can't be negative.
1s? thats it?
First off, let’s do the exponents rule of multiplication on the top \((3s^{-3})^5\) to \(3s^{-3+5}\) which equals \(3s^2\) Now we can add that back to the equation \(\dfrac{3s^2}{3s^{-2}}\) Use the rule of exponents for division \(\dfrac{3s^2}{3s^{-2}\) (subtract the exponents) \(\dfrac{3s}{3s}^0\) Now we can simplify it by division and you would get \(1s^0\)
I tried to help but i honestly don't know sorry
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You want me to try just 1s?
The exponents would just be zero if you go by the rules Multiplication: add Division: subtraction
Okay
Let me try 1s then.
Yes that was right thank you.
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No problem ^^
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