Question

MAthz

Answer 1

multiply x by everything in the other parenthesis and -2 by everything in the parenthesis
then combine like terms

Answer 2

I tried that but its confusing. If i go step by step what Im doing can you help

Answer 3

Ok let me write it down on paper

Answer 4

Ok so I'm doing X * \[2x^2\] I'm not sure would that be \[3x^2\] or something else

Answer 5

(x-2)(2x^2-x-3)
first lets multiply x by everything in the other parenthesis
x(2x^2 - x - 3 )
x * 2x^2 = 2x^3
x * -x = -x^2
x * -3 = -3x
So we have 2x^3 - x^2 - 3x

We then do the same thing with -2
-2(2x^2 - x - 3)
-2 * 2x^2 = -4x^2
-2 * -x = 2x
-2 * -3 = 6
We then have -4x^2 + 2x + 6

We then add the two expressiong together
(2x^3 - x^2 - 3x) + (-4x^2 + 2x + 6)
remove parenthesis
2x^3 - x^2 - 3x -4x^2 + 2x + 6
combine like terms ( like terms are terms with the same variable as well as exponent )
an example of like terms is 2x^2 and 4x^2, they both have a variable of x and a power of 2

-x^2 and -4x^2 are like terms so we combine them
-x^2 + -4x^2 = -5x^2
2x and -3x are like terms so we combine them
2x - 3x = -x
We're left with 2x^3 - 5x^2 - x + 6

Answer 6

That was right. I had to try and see what you did on paper. Thanks for your help mark