Question

Calculate the mass of 6.9 moles of nitrous acid (HNO2). Explain the process or show your work by including all values used to determine the answer.

Answer 1

The mass of a mole of an element is equal to the average atomic mass of an element which can be found on a periodic table ( in grams )

Answer 2

Ex Hydrogen has an atomic mass of 1.008
So 1 mole of hydrogen weighs 1.008 g

Given this find the mass of 1 atom of Hydrogen(H) , 1 atom of Nitrogen (N) and 2 atoms of oxygen (O) and then multiply that by 6.9

Answer 3

The parts you explained makes sense,but are you in any way able to present the process of what the question asked up above or.....?

Answer 4

First lets find the mass of 1 mole of HNO2
Like stated previously the mass of 1 atom of an element is equal to the mass of a mole of an element ( in grams )
First lets find the mass of 1 mole of each individual element
So 1 mole of Hydrogen has a mass of 1.008 g
1 mole of Nitrogen has a mass of 14.007
and 1 mole of oxygen has 15.999 ( bc there are two atoms of oxygen we multiply by 2 ) 2 * 15.999 which equals 31.998 g

Finally we add the masses together to get the mass of 1 mole of HNO2
31.998 + 14.007 + 1.008 = 47.013g
So one mole of HNO2 has a mass of 47.013
We want to find the mass of 6.9 moles of HNO2
47.013 x 6.9 = 324.3897
The answer would be 324.3897 g/mol

Answer 5

@swaggymark ,is that all to it ;or is there anything else to be clarified?

Answer 6

Thats pretty much it, first you find the molar mass of each individual element. If there is a number after the element in the formula then you multiply by whatever that number is
Ex HNO2
There are two atoms of oxygen so you multiply the mass of oxygen by 2
ANd then you add all the masses together to get the mass of the compound
Then you multiply the compound mass by the number of moles you are trying to find.

Answer 7

Alltogether,I would like to thank you very much.For even taking time out of your day and having the patience to still stay and help in any way you could have.You were the only one that helped me when I needed it the most,and thank you again I really appreciate it.Overall,have a good rest of your day @swaggymark .

Answer 8

No problem!