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Mathematics 14 Online
Serenity1jacksonsl:

Help me pleaseeeee

Serenity1jacksonsl:

martai:

just see which one equals x=6

Serenity1jacksonsl:

i tryed bhutt its not working

martai:

ok let me see what i can do

Serenity1jacksonsl:

thank you

martai:

ok for the first one

lifewmylilweeb:

ok ill help you

martai:

u have 6x=12

Serenity1jacksonsl:

the first one is not equal thoe idk so

martai:

correct

lifewmylilweeb:

for the first one you have to divide 6 on both sides

martai:

which was ?

lifewmylilweeb:

which would be x=2

martai:

mhm

lifewmylilweeb:

so the first one is incorrect

Serenity1jacksonsl:

so the second one

martai:

17-x=11

lifewmylilweeb:

for the second one you have to subtract 17 from both sides

lifewmylilweeb:

and you would get -x=-6 then you would have to divide -1 by both sides

Serenity1jacksonsl:

@lifewmylilweeb wrote:
for the second one you have to subtract 17 from both sides
so its not correct

lifewmylilweeb:

and what would you get?

lifewmylilweeb:

@serenity1jacksonsl wrote:
@lifewmylilweeb wrote:
for the second one you have to subtract 17 from both sides
so its not correct
it is correct

martai:

then u have x/2=3

martai:

Multiply all terms by the same value to eliminate fraction denominators

Serenity1jacksonsl:

@martai wrote:
then u have x/2=3
so when i divided that it did not equal

martai:

then u wanna do is

lifewmylilweeb:

for the third one you have to multiply 2 by both sides

martai:

then u will get your answer which is?

lifewmylilweeb:

so you have to solve this for the thrid one \[\frac{ 2x }{ 2 }=3*2\]

lifewmylilweeb:

so what would you get?

baconway:

It says x = 6 so wouldn't you just put 6/2=3 and then that would be true bc you replaced the x with the 6 bc x=6

baconway:

and then do that with the rest of them right?

lifewmylilweeb:

@baconway wrote:
and then do that with the rest of them right?
no for each one you have to solve it a different way

GalaxyzStarz:

Okay, so I see what's happening here. \[6(x)=12\] Replace 6 with x. \[6(6)=36\] So, that makes the first answer choice incorrect. \[17-(x)=11\] Replace 6 with x. \[17-(6)=11\] That makes the second answer choice correct! \[(x)\div2=3\] Replace 6 with x. \[6\div2=3\] That makes the third answer choice correct! \[19\div3=(x)\] Replace 6 with x. \[19\div3=6.3333\] So, that makes the fourth answer choice incorrect. \[5+(x)=11\] Replace 6 with x. \[5+(6)=11\] That makes the fifth answer choice correct! I hope this helps that question you were trying to solve!

baconway:

I told them thats how to do it and they said I was wrong

Jeimmy:

The 2nd one. The 3rd one And the last one

GalaxyzStarz:

@thisgirlpretty, I don't know if you can do this, but can you delete some of these comments? They crowd the post, may you also check my work? Thanks.

GalaxyzStarz:

Please.

ThisGirlPretty:

Only mods can delete the comments

GalaxyzStarz:

Suggestion to ping?

GalaxyzStarz:

Maybe that last comment wasn't clear, (not trying to sound rude in any way.) But, I was meaning, do you have a suggestion of who I should ping?

ThisGirlPretty:

@vocaloid

surjithayer:

1. 6x=12 x=12/6=2 2. 17-x=11 17-11=x x=6 3. \[x \div2=3\]\[x=2\times3=6\] 4. \[19\div3=x \]\[ x=19/3\neq 6\] 5. 5+x=11 x=11-5 x=6 2nd,3rd,5th are correct.

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