Question

Solve the following system of equations and show all work.

y = x2 + 3
y = x + 5

Answer 1

is it supposed to be x squared?
or 2x

Answer 2

\[y=x^2+3\]
\[y=x+5\]

Answer 3

Since they both equal y, set both of them equal to each other.
\[x^2+3=x+5\]
\[x^2-x-2=0\]
\[(x-2)(x+1)=0\]
The two solutions would be:
\[x-2=0\]
\[x=2\]
and
\[x+1=0\]
\[x=-1\]
I hope this cleared up a bit of confusion.

Answer 4

both equal y meaning that the equations are equal to each other
so x^2 + 3 = x + 5
because there is an exponent we are going to have to put the equation in quadratic form ax^2 + + bx + c
x^2 + 3 = x + 5
subtract x from both sides
x^2 - x + 3 = 5
subtract 5 from both sides
x^2 - x - 2
we can then factor to get
(x+1)(x-2)=0
we then solve each factor
x-2 = 0 x + 1 = 0
add 2 to both sides subtract 1 from both sides
x = 2 and x = -1

Answer 5

As well as to @swaggymark ,sorry about that;and to everyone else that tried their best to help.Farewell to all.