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Consider the reaction 2CuCl2 + 4KI → 2CuI + 4KCl + I2. If 4 moles of CuCl2 react with 4 moles of KI, what is the limiting reactant? a CuCl2 b KI c CuI d I2
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2CuCl2 + 4KI → 2CuI + 4KCl + I2 You use 2 moles of CuCl2 and 4 moles of KI to make the products You're starting off with 4 moles of CuCl2 and 4 moles of KI How much of the reactants do you have left?
Let's re-word the question then for you to understand it
2 apples + 4 bananas ---> 2 cupcakes + 4 pies + 1 cake You have 4 apples and 4 bananas To make 2 cupcakes, 4 pies, and 1 cake, how many apples and bananas do you need?
Use Tranquility's examples.
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