Question

A chemist reacted 57.50 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is shown.

Na + Cl2 → NaCl

If the percentage yield of the reaction is 86%, what is the actual yield? Show your work, including the use of stoichiometric calculations and conversion factors.

Answer 1

@vocaloid

Answer 2

1. balance the equation
2. start with 57.50g Na, convert to moles by dividing by the molar mass of Na
3. use the balanced equation to convert moles Na to moles NaCl produced
4. convert moles NaCl produced to grams NaCl by multiplying by the molar mass of NaCl. this is the theoretical yield of NaCl.
5. multiply the theoretical yield the previous step by 86% to get the actual yield

Answer 3

@tranquility