Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen. In an experiment, the molar mass of the compound was determined to be 118.084 g/mol. What is the molecular formula of the compound? For both questions, show your work or explain how you determined the formulas by giving specific values used in calculations.
Answer is coming
sorry im taking so long
is it hydrogen peroxide or just hydrogen,because there are different chemical versions of hydrogen
The atomic mass of carbon is 12.01 g/mol. As shown on the periodic table the atomic number is 6,so you need to multiply the atomic mass,12.01 g/mol by the atomic mass,which is 6,to get the total mass contribution.Therefore the total mass contribution is 72.06 g/mol.Do the same thing for the 5.1 g/mol of hydrogen,and the 54.2 g/mol of oxygen.Since 5.1 only has 1 proton and no neutrons,the total mass contribution is 5.1 g/mol (s).Finally,now that we have concrete knowledge of the formula for total mass contribution.We can deduce that 54.2 g/ mol times 8(atomic mass,a single oxygen atom has eight protons, eight neutrons and eight electrons. The number of protons and electrons of an element are equal to its atomic number) will equal a total mass contribution of 443.6 g/mol.Now,we need to find the molecular mass.The molecular mass is the sum of each total mass contribution.So add them up and the molecular mass equals 510.76 g/mol. To find the mass percent composition of an element, divide the mass contribution of the element by the total molecular mass. The number must then be multiplied by 100% to be expressed as a percent.So the equation is\[carbon's \space mass \space percentage=12.01g/mol/72.06g/mol=0.17 times space 100 space percent = 0.17 space percent\] \[hydrogen's \space mass \space percentage \space composition=5.1g/mol/1g/ mol= 5.1g/m \times 100=5.1 \space percent\] and \[oxygen's s \space mass \space contribution=510.76g/mol/8g/mol=63.845=63.85 \times 8=510.8 \space which \space is \space 510.76 \space rounded \space \to the tenths place\] Done,Make sure to paraphrase or shorten
Thank you very much @velmalovesshaggy145 .Have a great rest of your day.Thank you for your time and patience throughout.
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