Factoring. Again.
\[5y^2z-42x^4y^5\]
@florisalreadytaken
i'm not sure...if i pinged this person right...lmao
Idek if i pinged you right or not.
I can't find a gcf.
no, it's fine you see the two terms only have got \(y ^2\) in common
Yes.
right, and you remember that \( a^{b+c}=a^{b} \times a^{c} \) applying the rule we get \( y^5=y^2 \times y^3 \) for the second term you can finish it
hmm let me see here. we would take out 2. then in the parenthesis, uh...
I'm confused sorry.
What do we do with the numbers....
do we just bring them down?
well, there's no GFC between 5 and 42 other than one as far as I am concerned, but if you came up with any theory, i wouldn't mind knowing!
I have no idea...tbh.
knowing that only \(y^2\) is common we could just simplify it: \( 5y^2z-42x^4y^5 \ \ = \ \ 5y^2z-42x^4y^2y^3 \) and here we can simplify the \(y^2\) \(\boxed{y^2\left(5z-42x^4y^3\right)}\)
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