Ik the order is off. Its 2+2x how you know it. But It would take it either way
Questionnare:
Obviously, you cannot write 2xx.
UkuleleGirl:
I didn't write 2 xx
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Questionnare:
@ukulelegirl wrote:
I didn't write 2 xx
I know.
UkuleleGirl:
its either 2x or \(x^2\)
Hero:
Okay let me show you a little trick for these. Suppose you have something like \(5x - 4x + 5x\) and they ask you to "Combine Like Terms". What you can do is factor out the common term until you have nothing but coefficients or numbers to either add or subtract. So for example,
\(5x - 4x + 3x\) becomes \((5 - 4 + 3)x\) and now it is obvious to just add/subtract the numbers in parentheses to get \(4x\) as the simplified expression.
UkuleleGirl:
That makes sense.
Hero:
More examples:
\(7x + 3x - 4x\) becomes \((7 + 3 - 4)x\) which reduces to \((10 - 4)x\) or simply \(6x\).
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Hero:
So you can apply this same logic to your problem.
UkuleleGirl:
Yes
UkuleleGirl:
but theres only one number. and 2 variables. which is why i said its either 2+2x or 2+\(x^2\)
Hero:
@ukulelegirl wrote:
but theres only one number. and 2 variables. which is why i said its either 2+2x or 2+\(x^2\)
False. If you have something like \(x + 5x + x\), when you factor out \(x\) it becomes \((1 + 5 + 1)x\).
UkuleleGirl:
oh, so it would become (1+2+1)x
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Hero:
@ukulelegirl wrote:
oh, so it would become (1+2+1)x
Correct
UkuleleGirl:
that would be 3x
Hero:
@ukulelegirl wrote:
that would be 3x
Incorrect
UkuleleGirl:
wait no 4
UkuleleGirl:
I miscounted
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Hero:
@ukulelegirl wrote:
I miscounted
Okay
UkuleleGirl:
its 4x
Questionnare:
@ukulelegirl wrote:
its 4x
Yes!
Hero:
All of math essentially comes down to "counting". So make sure you do that part right.
UkuleleGirl:
Yayyy
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Hero:
I showed you this trick to make it easier for you to count.
UkuleleGirl:
heroo...it said it was wrong
Questionnare:
! Maybe you didn't factor right or did the wrong arrangement.
UkuleleGirl:
you don't factor here
Hero:
That's because the answer is \(2 + 2x\)
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Questionnare:
Yes. Not 2x + 2
UkuleleGirl:
uh.....
UkuleleGirl:
the order in delta mathdoesn't matter
Hero:
The answer is \(2 + 2x\) or \(2x + 2\). I forgot to tell you your original answer was correct as written. I only showed you the "trick" to make it easier for you these problems. But you have to keep up with which terms are "like".
Questionnare:
Hm.
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UkuleleGirl:
Yea
Questionnare:
Okay.
x + 2 + x
two x'es
add like terms.
2x + 2
or
2 + 2x
UkuleleGirl:
I got it.
Hero:
@hero wrote:
I showed you this trick to make it easier for you to count.
Next time I will verify your work before showing you any tricks.