help

Question

help

TETSXPREME · Answer

attachment

J4ke · Answer

i was wrong ??? you posted the same question twice why?

TETSXPREME · Answer

no this is a different one

J4ke · Answer

Ok look for this one you have to replace x and y in the equations suggested. 
(0,0) and (5,-2) do you know how?

TETSXPREME · Answer

no

J4ke · Answer

You have to check if the equations are true or false by replacing x and y in the equations with  their values from the coordinates  given im writing with the equation editor so bare with me

YRJ8498 · Answer

Would we find the answer or equation using Point Slope Formula?

J4ke · Answer

Lets check if A is right or wrong follow the steps for the rest suggestions given.
$$y=-\frac{ 5 }{ 2 }x$$
first we have (x,y) (0,0)
$$0=-\frac{ 5 }{ 2 }(0)$$
0=0

$$-2=-\frac{ 5 }{ 2 }(5)$$
-2$$-2\neq-12.5$$
so A is wrong

J4ke · Answer

lets move to B same steps

J4ke · Answer

I'm going to solve the right one i cant write the same equation multiple time
D
$$y=-\frac{ 2 }{ 5 }x$$
first we have (x,y) (0,0)
$$0=-\frac{ 2 }{ 5 }(0)$$
0=0

$$-2=-\frac{ 2 }{ 5}(5)$$
-2=-2
so D is the answer

Florisalreadytaken · Answer

why take every option when you just find the m directly

$A(0, \ 0)     \ \    ---- \ \    A(X, \ Y)$

$B(5, \ -2)    \     --- \ \    B(X, \ Y)$

$m_{AB}=\dfrac{Y_B-YA}{X_B-X_A} \ \ = \ \ \ \dfrac{-2-0}{5-0}=\dfrac{-2}{5}   $
<hr class="bbcode_rule" />

$ y=mx+c  $ where $\boxed{c=0} \ \ \& \ \   \boxed{m=\dfrac{-2}{5}}   $

therefore

$ y=\dfrac{-2}{5}x+0 $   or simply $\boxed{y=-\dfrac{2}{5}x} $

J4ke · Answer

@florisalreadytaken wrote:

why take every option when you just find the m directly $A(0, \ 0) \ \ ---- \ \ A(X, \ Y)$ $B(5, \ -2) \ --- \ \ B(X, \ Y)$ $m_{AB}=\dfrac{Y_B-YA}{X_B-X_A} \ \ = \ \ \ \dfrac{-2-0}{5-0}=\dfrac{-2}{5} $ $ y=mx+c $ where $\boxed{c=0} \ \ \& \ \ \boxed{m=\dfrac{-2}{5}} $ therefore $ y=\dfrac{-2}{5}x+0 $ or simply $\boxed{y=-\dfrac{2}{5}x} $

seems like you have been using the equation editor for years lmao good job

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