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hamidiso23:
i answered
UkuleleGirl:
okay okay :)
Joe348:
Yes i know what it is
hamidiso23:
what is it?
UkuleleGirl:
Let me find a pencil rq please
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Joe348:
finding greatest common factor
hamidiso23:
ye
Joe348:
@carmelle come back ;-;
UkuleleGirl:
IM here now
UkuleleGirl:
ok so this is what were going to do.
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UkuleleGirl:
were going to take 12 and -3. and see if either of them have a gcf.
Joe348:
okay?>
UkuleleGirl:
The gcf would be 3
Joe348:
tbh im not understanding
UkuleleGirl:
okay
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UkuleleGirl:
so what I did, was divide 12, by each number up until 9.
UkuleleGirl:
so I did, 12/2 12/3 12/4 etc
UkuleleGirl:
I did the same with 3
Joe348:
okay i got that
UkuleleGirl:
So what areyou not getting so far?
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UkuleleGirl:
is it the x part?
Joe348:
Im not understanding what we are factoring
Joe348:
like what is the 0 for?
UkuleleGirl:
0?
UkuleleGirl:
Where did you get 0
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Joe348:
okay just solve the problem and ill follow along to see if i understand
UkuleleGirl:
okay
Joe348:
@ukulelegirl wrote:
Where did you get 0
the 0 at the end?
UkuleleGirl:
OOOOOOOoh
UkuleleGirl:
i'm dumb;-;
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UkuleleGirl:
Well. We just setit equal to 0 in factoring.
Joe348:
so is it?? \[12x^3-3x=-12x^3-3x^2\]
UkuleleGirl:
no...
UkuleleGirl:
lets justleave the 0 alone rn
UkuleleGirl:
ok so what were going to do is take out 2 x's
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UkuleleGirl:
in factoring.
Joe348:
from what I got, I got 0 as my answer
UkuleleGirl:
it would look like this:\[3x^2(4+x)=0\) If im correct
UkuleleGirl:
wait
UkuleleGirl:
wroteit wrong
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UkuleleGirl:
\[3x^2(4+x)=0\]
Timmyspu:
The more I watch you do this the more I am confused. xd
UkuleleGirl:
how
UkuleleGirl:
i can tell you where i getthe numbers
Timmyspu:
No its ok. I understand its just how much your posting confuses me. xd
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UkuleleGirl:
oh
Joe348:
@ukulelegirl wrote:
\[3x^2(4+x)=0\]
I think I understand how you got that
UkuleleGirl:
Explain to me?
Joe348:
me?
UkuleleGirl:
Yes. If you know how please explain so Ik uk how to do it
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Joe348:
actually nvm im still confused
UkuleleGirl:
oh..
UkuleleGirl:
okay so this is how i got it.
UkuleleGirl:
I took the 12 and 3 and factored out a 3. I took the \(x^3\) and factored out \(x^2\) I did 3 divided by 12 and got 4, and then added the remaining x.
carmelle:
I feel like UkuleleGirl made this way more confusing than it is.
I don't see why he has to explain something you just explained to him...
But, moving on, here are the steps UkuleleGirl took.
First, they found the greatest common factor of 12 and -3 and they got 3.
\[(3x^2)(4+x)=0\]
Now that you know that, all you do next is to set them equal to 0 and solve.
\[(3x^2)=0\]
\[(4x-1)=0\]
So just solve for x.
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Joe348:
the second equation only?
carmelle:
this is for the first question btw
Joe348:
yes i figured and thank you
UkuleleGirl:
0-0
Joe348:
@carmelle wrote:
I feel like UkuleleGirl made this way more confusing than it is.
I don't see why he has to explain something you just explained to him...
But, moving on, here are the steps UkuleleGirl took.
First, they found the greatest common factor of 12 and -3 and they got 3.
\[(3x^2)(4+x)=0\]
Now that you know that, all you do next is to set them equal to 0 and solve.
\[(3x^2)=0\]
\[(4x-1)=0\]
So just solve for x.
im confused on how to solve for x
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Joe348:
okay for the second part i got \[1/4\]
carmelle:
ok, for the first one, divide both sides by 3
so, \[\frac{ 3x^2 }{ 3 }=\frac{ 0 }{ 3 }\]
Now we have \[x^2=0\]
However, there is a rule that states that...
\[x^n =0 \rightarrow x=0\]
So your final answers are x = 0 and x = 1/4