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Mathematics 8 Online
Joe348:

solve by factoring

Joe348:

1 attachment
UkuleleGirl:

So do gcf. Do you know what gcf is?

hamidiso23:

greatest common factor

UkuleleGirl:

I'm not asking you

hamidiso23:

ik

hamidiso23:

i answered

UkuleleGirl:

okay okay :)

Joe348:

Yes i know what it is

hamidiso23:

what is it?

UkuleleGirl:

Let me find a pencil rq please

Joe348:

finding greatest common factor

hamidiso23:

ye

Joe348:

@carmelle come back ;-;

UkuleleGirl:

IM here now

UkuleleGirl:

ok so this is what were going to do.

UkuleleGirl:

were going to take 12 and -3. and see if either of them have a gcf.

Joe348:

okay?>

UkuleleGirl:

The gcf would be 3

Joe348:

tbh im not understanding

UkuleleGirl:

okay

UkuleleGirl:

so what I did, was divide 12, by each number up until 9.

UkuleleGirl:

so I did, 12/2 12/3 12/4 etc

UkuleleGirl:

I did the same with 3

Joe348:

okay i got that

UkuleleGirl:

So what areyou not getting so far?

UkuleleGirl:

is it the x part?

Joe348:

Im not understanding what we are factoring

Joe348:

like what is the 0 for?

UkuleleGirl:

0?

UkuleleGirl:

Where did you get 0

Joe348:

okay just solve the problem and ill follow along to see if i understand

UkuleleGirl:

okay

Joe348:

@ukulelegirl wrote:
Where did you get 0
the 0 at the end?

UkuleleGirl:

OOOOOOOoh

UkuleleGirl:

i'm dumb;-;

UkuleleGirl:

Well. We just setit equal to 0 in factoring.

Joe348:

so is it?? \[12x^3-3x=-12x^3-3x^2\]

UkuleleGirl:

no...

UkuleleGirl:

lets justleave the 0 alone rn

UkuleleGirl:

ok so what were going to do is take out 2 x's

UkuleleGirl:

in factoring.

Joe348:

from what I got, I got 0 as my answer

UkuleleGirl:

it would look like this:\[3x^2(4+x)=0\) If im correct

UkuleleGirl:

wait

UkuleleGirl:

wroteit wrong

UkuleleGirl:

\[3x^2(4+x)=0\]

Timmyspu:

The more I watch you do this the more I am confused. xd

UkuleleGirl:

how

UkuleleGirl:

i can tell you where i getthe numbers

Timmyspu:

No its ok. I understand its just how much your posting confuses me. xd

UkuleleGirl:

oh

Joe348:

@ukulelegirl wrote:
\[3x^2(4+x)=0\]
I think I understand how you got that

UkuleleGirl:

Explain to me?

Joe348:

me?

UkuleleGirl:

Yes. If you know how please explain so Ik uk how to do it

Joe348:

actually nvm im still confused

UkuleleGirl:

oh..

UkuleleGirl:

okay so this is how i got it.

UkuleleGirl:

I took the 12 and 3 and factored out a 3. I took the \(x^3\) and factored out \(x^2\) I did 3 divided by 12 and got 4, and then added the remaining x.

carmelle:

I feel like UkuleleGirl made this way more confusing than it is. I don't see why he has to explain something you just explained to him... But, moving on, here are the steps UkuleleGirl took. First, they found the greatest common factor of 12 and -3 and they got 3. \[(3x^2)(4+x)=0\] Now that you know that, all you do next is to set them equal to 0 and solve. \[(3x^2)=0\] \[(4x-1)=0\] So just solve for x.

Joe348:

the second equation only?

carmelle:

this is for the first question btw

Joe348:

yes i figured and thank you

UkuleleGirl:

0-0

Joe348:

@carmelle wrote:
I feel like UkuleleGirl made this way more confusing than it is. I don't see why he has to explain something you just explained to him... But, moving on, here are the steps UkuleleGirl took. First, they found the greatest common factor of 12 and -3 and they got 3. \[(3x^2)(4+x)=0\] Now that you know that, all you do next is to set them equal to 0 and solve. \[(3x^2)=0\] \[(4x-1)=0\] So just solve for x.
im confused on how to solve for x

Joe348:

okay for the second part i got \[1/4\]

carmelle:

ok, for the first one, divide both sides by 3 so, \[\frac{ 3x^2 }{ 3 }=\frac{ 0 }{ 3 }\] Now we have \[x^2=0\] However, there is a rule that states that... \[x^n =0 \rightarrow x=0\] So your final answers are x = 0 and x = 1/4

Joe348:

Thank you mello<3

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